kornShell and AIX unable to create an Array Variable
Clash Royale CLAN TAG#URR8PPP
LS=`ls "$SRC_PATH"/* | grep -i -v *.ignore`
I cannot use for loop as I need to check conditions with while as there are multiple conditions.
Trying to access the content using
$LS[$CNT]
CNT=`expr $CNT + 1`
I am unable to access the contents.
aix array
edited Jan 12 at 1:08
Rui F Ribeiro
39.6k1479132
asked Jan 11 at 22:38
Bootham DeyyamBootham Deyyam
111
add a comment |
LS=`ls "$SRC_PATH"/* | grep -i -v *.ignore`
I cannot use for loop as I need to check conditions with while as there are multiple conditions.
Trying to access the content using
$LS[$CNT]
CNT=`expr $CNT + 1`
I am unable to access the contents.
aix array
edited Jan 12 at 1:08
Rui F Ribeiro
39.6k1479132
asked Jan 11 at 22:38
Bootham DeyyamBootham Deyyam
111
add a comment |
LS=`ls "$SRC_PATH"/* | grep -i -v *.ignore`
I cannot use for loop as I need to check conditions with while as there are multiple conditions.
Trying to access the content using
$LS[$CNT]
CNT=`expr $CNT + 1`
I am unable to access the contents.
aix array
edited Jan 12 at 1:08
Rui F Ribeiro
39.6k1479132
asked Jan 11 at 22:38
Bootham DeyyamBootham Deyyam
111
LS=`ls "$SRC_PATH"/* | grep -i -v *.ignore`
I cannot use for loop as I need to check conditions with while as there are multiple conditions.
Trying to access the content using
$LS[$CNT]
CNT=`expr $CNT + 1`
I am unable to access the contents.
aix array
aix array
edited Jan 12 at 1:08
Rui F Ribeiro
39.6k1479132
asked Jan 11 at 22:38
Bootham DeyyamBootham Deyyam
111
edited Jan 12 at 1:08
Rui F Ribeiro
39.6k1479132
asked Jan 11 at 22:38
Bootham DeyyamBootham Deyyam
111
edited Jan 12 at 1:08
Rui F Ribeiro
39.6k1479132
edited Jan 12 at 1:08
Rui F Ribeiro
39.6k1479132
edited Jan 12 at 1:08
Rui F Ribeiro
39.6k1479132
39.6k1479132
asked Jan 11 at 22:38
Bootham DeyyamBootham Deyyam
111
asked Jan 11 at 22:38
Bootham DeyyamBootham Deyyam
111
asked Jan 11 at 22:38
Bootham DeyyamBootham Deyyam
111
111
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
We'll start with Do not parse the output of ls because it's always good to remind people of this.
Next note that the grep probably isn't doing what you want; you likely want .ignore$ to make it skip files ending with ".ignore"
Since we're using ksh you don't need to call expr; you can just do let CNT=CNT+1
Now..
To set an array in ksh you need to use set -A syntax.
eg
set -A LS $(ls "$SRC_PATH"/* | grep -i -v '.ignore$')
Now $LS[0] will be the first file, etc etc.
eg if we have
$ ls X
a b c
Then
$ set -A LS $(ls X)
$ echo $LS[0]
a
$ echo $LS[1]
b
$ echo $LS[2]
c
answered Jan 11 at 22:50
Stephen HarrisStephen Harris
25.5k24477
Thank you very much, this worked.
– Bootham Deyyam
Jan 13 at 19:33
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
We'll start with Do not parse the output of ls because it's always good to remind people of this.
Next note that the grep probably isn't doing what you want; you likely want .ignore$ to make it skip files ending with ".ignore"
Since we're using ksh you don't need to call expr; you can just do let CNT=CNT+1
Now..
To set an array in ksh you need to use set -A syntax.
eg
set -A LS $(ls "$SRC_PATH"/* | grep -i -v '.ignore$')
Now $LS[0] will be the first file, etc etc.
eg if we have
$ ls X
a b c
Then
$ set -A LS $(ls X)
$ echo $LS[0]
a
$ echo $LS[1]
b
$ echo $LS[2]
c
answered Jan 11 at 22:50
Stephen HarrisStephen Harris
25.5k24477
Thank you very much, this worked.
– Bootham Deyyam
Jan 13 at 19:33
add a comment |
We'll start with Do not parse the output of ls because it's always good to remind people of this.
Next note that the grep probably isn't doing what you want; you likely want .ignore$ to make it skip files ending with ".ignore"
Since we're using ksh you don't need to call expr; you can just do let CNT=CNT+1
Now..
To set an array in ksh you need to use set -A syntax.
eg
set -A LS $(ls "$SRC_PATH"/* | grep -i -v '.ignore$')
Now $LS[0] will be the first file, etc etc.
eg if we have
$ ls X
a b c
Then
$ set -A LS $(ls X)
$ echo $LS[0]
a
$ echo $LS[1]
b
$ echo $LS[2]
c
answered Jan 11 at 22:50
Stephen HarrisStephen Harris
25.5k24477
Thank you very much, this worked.
– Bootham Deyyam
Jan 13 at 19:33
add a comment |
We'll start with Do not parse the output of ls because it's always good to remind people of this.
Next note that the grep probably isn't doing what you want; you likely want .ignore$ to make it skip files ending with ".ignore"
Since we're using ksh you don't need to call expr; you can just do let CNT=CNT+1
Now..
To set an array in ksh you need to use set -A syntax.
eg
set -A LS $(ls "$SRC_PATH"/* | grep -i -v '.ignore$')
Now $LS[0] will be the first file, etc etc.
eg if we have
$ ls X
a b c
Then
$ set -A LS $(ls X)
$ echo $LS[0]
a
$ echo $LS[1]
b
$ echo $LS[2]
c
answered Jan 11 at 22:50
Stephen HarrisStephen Harris
25.5k24477
We'll start with Do not parse the output of ls because it's always good to remind people of this.
Next note that the grep probably isn't doing what you want; you likely want .ignore$ to make it skip files ending with ".ignore"
Since we're using ksh you don't need to call expr; you can just do let CNT=CNT+1
Now..
To set an array in ksh you need to use set -A syntax.
eg
set -A LS $(ls "$SRC_PATH"/* | grep -i -v '.ignore$')
Now $LS[0] will be the first file, etc etc.
eg if we have
$ ls X
a b c
Then
$ set -A LS $(ls X)
$ echo $LS[0]
a
$ echo $LS[1]
b
$ echo $LS[2]
c
answered Jan 11 at 22:50
Stephen HarrisStephen Harris
25.5k24477
answered Jan 11 at 22:50
Stephen HarrisStephen Harris
25.5k24477
answered Jan 11 at 22:50
Stephen HarrisStephen Harris
25.5k24477
answered Jan 11 at 22:50
Stephen HarrisStephen Harris
25.5k24477
25.5k24477
Thank you very much, this worked.
– Bootham Deyyam
Jan 13 at 19:33
add a comment |
Thank you very much, this worked.
– Bootham Deyyam
Jan 13 at 19:33
Thank you very much, this worked.
– Bootham Deyyam
Jan 13 at 19:33
Thank you very much, this worked.
– Bootham Deyyam
Jan 13 at 19:33
add a comment |
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