Energy spacetime warping
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If energy warps spacetime, then does light warp spacetime?
And if special relativity says that things near the speed of light increase in relativistic mass, then does light have a relativistic mass?
Also, if energy warps spacetime then is it possible to have a black hole form from pure energy, instead of resulting from a massive object?
general-relativity energy visible-light spacetime curvature
edited Dec 30 '18 at 22:22
Qmechanic♦
102k121831163
asked Dec 30 '18 at 20:48
JamesJames
116
add a comment |
If energy warps spacetime, then does light warp spacetime?
And if special relativity says that things near the speed of light increase in relativistic mass, then does light have a relativistic mass?
Also, if energy warps spacetime then is it possible to have a black hole form from pure energy, instead of resulting from a massive object?
general-relativity energy visible-light spacetime curvature
edited Dec 30 '18 at 22:22
Qmechanic♦
102k121831163
asked Dec 30 '18 at 20:48
JamesJames
116
2
Consider to only ask one subquestion per post. Possible duplicate of subquestion 1: physics.stackexchange.com/q/22876/2451 . Possible duplicate of subquestion 3: physics.stackexchange.com/q/355890/2451 .
– Qmechanic♦
Dec 30 '18 at 22:26
add a comment |
If energy warps spacetime, then does light warp spacetime?
And if special relativity says that things near the speed of light increase in relativistic mass, then does light have a relativistic mass?
Also, if energy warps spacetime then is it possible to have a black hole form from pure energy, instead of resulting from a massive object?
general-relativity energy visible-light spacetime curvature
edited Dec 30 '18 at 22:22
Qmechanic♦
102k121831163
asked Dec 30 '18 at 20:48
JamesJames
116
If energy warps spacetime, then does light warp spacetime?
And if special relativity says that things near the speed of light increase in relativistic mass, then does light have a relativistic mass?
Also, if energy warps spacetime then is it possible to have a black hole form from pure energy, instead of resulting from a massive object?
general-relativity energy visible-light spacetime curvature
general-relativity energy visible-light spacetime curvature
edited Dec 30 '18 at 22:22
Qmechanic♦
102k121831163
asked Dec 30 '18 at 20:48
JamesJames
116
edited Dec 30 '18 at 22:22
Qmechanic♦
102k121831163
asked Dec 30 '18 at 20:48
JamesJames
116
edited Dec 30 '18 at 22:22
Qmechanic♦
102k121831163
edited Dec 30 '18 at 22:22
Qmechanic♦
102k121831163
edited Dec 30 '18 at 22:22
Qmechanic♦
102k121831163
102k121831163
asked Dec 30 '18 at 20:48
JamesJames
116
asked Dec 30 '18 at 20:48
JamesJames
116
asked Dec 30 '18 at 20:48
JamesJames
116
116
2
Consider to only ask one subquestion per post. Possible duplicate of subquestion 1: physics.stackexchange.com/q/22876/2451 . Possible duplicate of subquestion 3: physics.stackexchange.com/q/355890/2451 .
– Qmechanic♦
Dec 30 '18 at 22:26
add a comment |
2
Consider to only ask one subquestion per post. Possible duplicate of subquestion 1: physics.stackexchange.com/q/22876/2451 . Possible duplicate of subquestion 3: physics.stackexchange.com/q/355890/2451 .
– Qmechanic♦
Dec 30 '18 at 22:26
2
2
Consider to only ask one subquestion per post. Possible duplicate of subquestion 1: physics.stackexchange.com/q/22876/2451 . Possible duplicate of subquestion 3: physics.stackexchange.com/q/355890/2451 .
– Qmechanic♦
Dec 30 '18 at 22:26
Consider to only ask one subquestion per post. Possible duplicate of subquestion 1: physics.stackexchange.com/q/22876/2451 . Possible duplicate of subquestion 3: physics.stackexchange.com/q/355890/2451 .
– Qmechanic♦
Dec 30 '18 at 22:26
add a comment |
1 Answer
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Spacetime curvature is caused by the density and flow of energy and momentum. Light has all of these things, and so it causes a slight amount of spacetime curvature.
A photon of light with frequency $f$ has energy $E=hf$ where $h$ is Planck’s constant, so it can be defined to have a relativistic mass $E/c^2=hf/c^2$. But the whole concept of relativistic mass has become obsolete because it is confusing and accomplishes nothing. (Whenever you think “relativistic mass”, just think “energy” instead. They are proportional, and physicists often use units in which the proportionality constant is 1, so having these two concepts is pointless.) You should think of “mass” as the Lorentz-invariant mass, which for a photon is zero.
In principle, a sufficiently dense cloud of self-gravitating photons could collapse to form a black hole. There is no reason to believe that such photon clouds have ever existed in the universe. The black holes they would create would be the same as the black holes created by matter.
answered Dec 30 '18 at 20:59
G. SmithG. Smith
5,1241021
add a comment |
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Spacetime curvature is caused by the density and flow of energy and momentum. Light has all of these things, and so it causes a slight amount of spacetime curvature.
A photon of light with frequency $f$ has energy $E=hf$ where $h$ is Planck’s constant, so it can be defined to have a relativistic mass $E/c^2=hf/c^2$. But the whole concept of relativistic mass has become obsolete because it is confusing and accomplishes nothing. (Whenever you think “relativistic mass”, just think “energy” instead. They are proportional, and physicists often use units in which the proportionality constant is 1, so having these two concepts is pointless.) You should think of “mass” as the Lorentz-invariant mass, which for a photon is zero.
In principle, a sufficiently dense cloud of self-gravitating photons could collapse to form a black hole. There is no reason to believe that such photon clouds have ever existed in the universe. The black holes they would create would be the same as the black holes created by matter.
answered Dec 30 '18 at 20:59
G. SmithG. Smith
5,1241021
add a comment |
Spacetime curvature is caused by the density and flow of energy and momentum. Light has all of these things, and so it causes a slight amount of spacetime curvature.
A photon of light with frequency $f$ has energy $E=hf$ where $h$ is Planck’s constant, so it can be defined to have a relativistic mass $E/c^2=hf/c^2$. But the whole concept of relativistic mass has become obsolete because it is confusing and accomplishes nothing. (Whenever you think “relativistic mass”, just think “energy” instead. They are proportional, and physicists often use units in which the proportionality constant is 1, so having these two concepts is pointless.) You should think of “mass” as the Lorentz-invariant mass, which for a photon is zero.
In principle, a sufficiently dense cloud of self-gravitating photons could collapse to form a black hole. There is no reason to believe that such photon clouds have ever existed in the universe. The black holes they would create would be the same as the black holes created by matter.
answered Dec 30 '18 at 20:59
G. SmithG. Smith
5,1241021
add a comment |
Spacetime curvature is caused by the density and flow of energy and momentum. Light has all of these things, and so it causes a slight amount of spacetime curvature.
A photon of light with frequency $f$ has energy $E=hf$ where $h$ is Planck’s constant, so it can be defined to have a relativistic mass $E/c^2=hf/c^2$. But the whole concept of relativistic mass has become obsolete because it is confusing and accomplishes nothing. (Whenever you think “relativistic mass”, just think “energy” instead. They are proportional, and physicists often use units in which the proportionality constant is 1, so having these two concepts is pointless.) You should think of “mass” as the Lorentz-invariant mass, which for a photon is zero.
In principle, a sufficiently dense cloud of self-gravitating photons could collapse to form a black hole. There is no reason to believe that such photon clouds have ever existed in the universe. The black holes they would create would be the same as the black holes created by matter.
answered Dec 30 '18 at 20:59
G. SmithG. Smith
5,1241021
Spacetime curvature is caused by the density and flow of energy and momentum. Light has all of these things, and so it causes a slight amount of spacetime curvature.
A photon of light with frequency $f$ has energy $E=hf$ where $h$ is Planck’s constant, so it can be defined to have a relativistic mass $E/c^2=hf/c^2$. But the whole concept of relativistic mass has become obsolete because it is confusing and accomplishes nothing. (Whenever you think “relativistic mass”, just think “energy” instead. They are proportional, and physicists often use units in which the proportionality constant is 1, so having these two concepts is pointless.) You should think of “mass” as the Lorentz-invariant mass, which for a photon is zero.
In principle, a sufficiently dense cloud of self-gravitating photons could collapse to form a black hole. There is no reason to believe that such photon clouds have ever existed in the universe. The black holes they would create would be the same as the black holes created by matter.
answered Dec 30 '18 at 20:59
G. SmithG. Smith
5,1241021
edited Dec 30 '18 at 21:17
answered Dec 30 '18 at 20:59
G. SmithG. Smith
5,1241021
answered Dec 30 '18 at 20:59
G. SmithG. Smith
5,1241021
answered Dec 30 '18 at 20:59
G. SmithG. Smith
5,1241021
5,1241021
add a comment |
add a comment |
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Consider to only ask one subquestion per post. Possible duplicate of subquestion 1: physics.stackexchange.com/q/22876/2451 . Possible duplicate of subquestion 3: physics.stackexchange.com/q/355890/2451 .
– Qmechanic♦
Dec 30 '18 at 22:26