Searching all downloaded files in a file list
Clash Royale CLAN TAG#URR8PPP
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I've downloaded some files. I want to find out whether these file names are present in file.txt one by one. I've tried following command but not successful. I want to find out using xargs.
ls | xargs grep file.txt
How do I do that?
command-line xargs
asked Oct 28 '17 at 11:05
Nayab Basha Sayed
1035
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up vote
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down vote
favorite
I've downloaded some files. I want to find out whether these file names are present in file.txt one by one. I've tried following command but not successful. I want to find out using xargs.
ls | xargs grep file.txt
How do I do that?
command-line xargs
asked Oct 28 '17 at 11:05
Nayab Basha Sayed
1035
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I've downloaded some files. I want to find out whether these file names are present in file.txt one by one. I've tried following command but not successful. I want to find out using xargs.
ls | xargs grep file.txt
How do I do that?
command-line xargs
asked Oct 28 '17 at 11:05
Nayab Basha Sayed
1035
I've downloaded some files. I want to find out whether these file names are present in file.txt one by one. I've tried following command but not successful. I want to find out using xargs.
ls | xargs grep file.txt
How do I do that?
command-line xargs
asked Oct 28 '17 at 11:05
Nayab Basha Sayed
1035
asked Oct 28 '17 at 11:05
Nayab Basha Sayed
1035
asked Oct 28 '17 at 11:05
Nayab Basha Sayed
1035
asked Oct 28 '17 at 11:05
Nayab Basha Sayed
1035
1035
add a comment |Â
add a comment |Â
1 Answer
1
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0
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accepted
Though I'm not sure what exactly means your "one by one" but here is
Short ls + grep approach:
ls -1 | grep -wf - file.txt
-1-lsoption, lists one file per line-f file-grepoption, obtains patterns fromfile(or STDIN in case of passing-argument), one per line
The same could be written as:
grep -wf <(ls -1) file.txt
answered Oct 28 '17 at 11:11
RomanPerekhrest
22.5k12145
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
Though I'm not sure what exactly means your "one by one" but here is
Short ls + grep approach:
ls -1 | grep -wf - file.txt
-1-lsoption, lists one file per line-f file-grepoption, obtains patterns fromfile(or STDIN in case of passing-argument), one per line
The same could be written as:
grep -wf <(ls -1) file.txt
answered Oct 28 '17 at 11:11
RomanPerekhrest
22.5k12145
add a comment |Â
up vote
0
down vote
accepted
Though I'm not sure what exactly means your "one by one" but here is
Short ls + grep approach:
ls -1 | grep -wf - file.txt
-1-lsoption, lists one file per line-f file-grepoption, obtains patterns fromfile(or STDIN in case of passing-argument), one per line
The same could be written as:
grep -wf <(ls -1) file.txt
answered Oct 28 '17 at 11:11
RomanPerekhrest
22.5k12145
add a comment |Â
up vote
0
down vote
accepted
up vote
0
down vote
accepted
Though I'm not sure what exactly means your "one by one" but here is
Short ls + grep approach:
ls -1 | grep -wf - file.txt
-1-lsoption, lists one file per line-f file-grepoption, obtains patterns fromfile(or STDIN in case of passing-argument), one per line
The same could be written as:
grep -wf <(ls -1) file.txt
answered Oct 28 '17 at 11:11
RomanPerekhrest
22.5k12145
Though I'm not sure what exactly means your "one by one" but here is
Short ls + grep approach:
ls -1 | grep -wf - file.txt
-1-lsoption, lists one file per line-f file-grepoption, obtains patterns fromfile(or STDIN in case of passing-argument), one per line
The same could be written as:
grep -wf <(ls -1) file.txt
answered Oct 28 '17 at 11:11
RomanPerekhrest
22.5k12145
edited Oct 28 '17 at 11:23
answered Oct 28 '17 at 11:11
RomanPerekhrest
22.5k12145
answered Oct 28 '17 at 11:11
RomanPerekhrest
22.5k12145
answered Oct 28 '17 at 11:11
RomanPerekhrest
22.5k12145
22.5k12145
add a comment |Â
add a comment |Â
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