How to print of the text between the last occurence of a pair of patterns?

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0
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I am trying to print the lines between the last occurrence of two patterns into another file using sed. For example, if file1 contains the following:

StartPattern
1
2
3
EndPattern
4
5
StartPattern
6
7
8
EndPattern
9
10
StartPattern
11
12
13
EndPattern
14
15

I would like the output to be:

11
12
13

How can I do this with sed?

edited Sep 26 '17 at 16:17

RomanPerekhrest

22.5k12145

asked Sep 26 '17 at 16:00

A. B

224

cat file|sed -n 'H; /^StartPattern/h; $g;p;' |sed '1d' |sed '/EndPattern/q' |sed '$ d'
â€“Â Emilio Galarraga
Sep 26 '17 at 17:26

add a commentÂ |Â

up vote
0
down vote

favorite

I am trying to print the lines between the last occurrence of two patterns into another file using sed. For example, if file1 contains the following:

StartPattern
1
2
3
EndPattern
4
5
StartPattern
6
7
8
EndPattern
9
10
StartPattern
11
12
13
EndPattern
14
15

I would like the output to be:

11
12
13

How can I do this with sed?

edited Sep 26 '17 at 16:17

RomanPerekhrest

22.5k12145

asked Sep 26 '17 at 16:00

A. B

224

cat file|sed -n 'H; /^StartPattern/h; $g;p;' |sed '1d' |sed '/EndPattern/q' |sed '$ d'
â€“Â Emilio Galarraga
Sep 26 '17 at 17:26

add a commentÂ |Â

up vote
0
down vote

favorite

I am trying to print the lines between the last occurrence of two patterns into another file using sed. For example, if file1 contains the following:

StartPattern
1
2
3
EndPattern
4
5
StartPattern
6
7
8
EndPattern
9
10
StartPattern
11
12
13
EndPattern
14
15

I would like the output to be:

11
12
13

How can I do this with sed?

edited Sep 26 '17 at 16:17

RomanPerekhrest

22.5k12145

asked Sep 26 '17 at 16:00

A. B

224

I am trying to print the lines between the last occurrence of two patterns into another file using sed. For example, if file1 contains the following:

StartPattern
1
2
3
EndPattern
4
5
StartPattern
6
7
8
EndPattern
9
10
StartPattern
11
12
13
EndPattern
14
15

I would like the output to be:

11
12
13

How can I do this with sed?

text-processing awk sed

edited Sep 26 '17 at 16:17

RomanPerekhrest

22.5k12145

asked Sep 26 '17 at 16:00

A. B

224

edited Sep 26 '17 at 16:17

RomanPerekhrest

22.5k12145

asked Sep 26 '17 at 16:00

A. B

224

edited Sep 26 '17 at 16:17

RomanPerekhrest

22.5k12145

edited Sep 26 '17 at 16:17

RomanPerekhrest

22.5k12145

edited Sep 26 '17 at 16:17

RomanPerekhrest

22.5k12145

asked Sep 26 '17 at 16:00

A. B

224

asked Sep 26 '17 at 16:00

A. B

224

asked Sep 26 '17 at 16:00

A. B

224

cat file|sed -n 'H; /^StartPattern/h; $g;p;' |sed '1d' |sed '/EndPattern/q' |sed '$ d'
â€“Â Emilio Galarraga
Sep 26 '17 at 17:26

add a commentÂ |Â

cat file|sed -n 'H; /^StartPattern/h; $g;p;' |sed '1d' |sed '/EndPattern/q' |sed '$ d'
â€“Â Emilio Galarraga
Sep 26 '17 at 17:26

cat file|sed -n 'H; /^StartPattern/h; $g;p;' |sed '1d' |sed '/EndPattern/q' |sed '$ d'
â€“Â Emilio Galarraga
Sep 26 '17 at 17:26

add a commentÂ |Â

2 Answers
2

active

oldest

votes

up vote
0
down vote

accepted

With single awk process:

awk '/StartPattern/ f=1;r=""; next f && /EndPattern/f=0
 f r=(r=="")? $0: r RS $0 END print r ' file > output

output file contents:

11
12
13

Alternative tac + awk solution:

tac file | awk '/StartPattern/exit/EndPattern/f=1;nextf' | tac > output

edited Sep 26 '17 at 16:24

answered Sep 26 '17 at 16:05

RomanPerekhrest

22.5k12145

This works if the End Pattern is the last line of the file. I realize my original post (which is now editted) was misleading. How can I only extract what's in between the patterns and not the rest of the file if there are lines below the last EndPattern?
â€“Â A. B
Sep 26 '17 at 16:12

@A.B, it will work even if EndPattern is not the last line. You need to test
â€“Â RomanPerekhrest
Sep 26 '17 at 16:14

Your first answer (tac+awk) prints: 11 12 13 14 15. However, your new answer (single awk) gives the correct output.
â€“Â A. B
Sep 26 '17 at 16:22

@A.B, I can not see the issue. Look here ibb.co/bTqUYk
â€“Â RomanPerekhrest
Sep 26 '17 at 16:27

add a commentÂ |Â

up vote
0
down vote

cat file |sed -n 'H; /^StartPattern/h; $g;p;' |sed -e '1d' -e '/EndPattern/q' |sed '$ d'

answered Sep 26 '17 at 17:37

Emilio Galarraga

32628

add a commentÂ |Â

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

up vote
0
down vote

accepted

With single awk process:

awk '/StartPattern/ f=1;r=""; next f && /EndPattern/f=0
 f r=(r=="")? $0: r RS $0 END print r ' file > output

output file contents:

11
12
13

Alternative tac + awk solution:

tac file | awk '/StartPattern/exit/EndPattern/f=1;nextf' | tac > output

edited Sep 26 '17 at 16:24

answered Sep 26 '17 at 16:05

RomanPerekhrest

22.5k12145

This works if the End Pattern is the last line of the file. I realize my original post (which is now editted) was misleading. How can I only extract what's in between the patterns and not the rest of the file if there are lines below the last EndPattern?
â€“Â A. B
Sep 26 '17 at 16:12

@A.B, it will work even if EndPattern is not the last line. You need to test
â€“Â RomanPerekhrest
Sep 26 '17 at 16:14

Your first answer (tac+awk) prints: 11 12 13 14 15. However, your new answer (single awk) gives the correct output.
â€“Â A. B
Sep 26 '17 at 16:22

@A.B, I can not see the issue. Look here ibb.co/bTqUYk
â€“Â RomanPerekhrest
Sep 26 '17 at 16:27

add a commentÂ |Â

up vote
0
down vote

accepted

With single awk process:

awk '/StartPattern/ f=1;r=""; next f && /EndPattern/f=0
 f r=(r=="")? $0: r RS $0 END print r ' file > output

output file contents:

11
12
13

Alternative tac + awk solution:

tac file | awk '/StartPattern/exit/EndPattern/f=1;nextf' | tac > output

edited Sep 26 '17 at 16:24

answered Sep 26 '17 at 16:05

RomanPerekhrest

22.5k12145

This works if the End Pattern is the last line of the file. I realize my original post (which is now editted) was misleading. How can I only extract what's in between the patterns and not the rest of the file if there are lines below the last EndPattern?
â€“Â A. B
Sep 26 '17 at 16:12

@A.B, it will work even if EndPattern is not the last line. You need to test
â€“Â RomanPerekhrest
Sep 26 '17 at 16:14

Your first answer (tac+awk) prints: 11 12 13 14 15. However, your new answer (single awk) gives the correct output.
â€“Â A. B
Sep 26 '17 at 16:22

@A.B, I can not see the issue. Look here ibb.co/bTqUYk
â€“Â RomanPerekhrest
Sep 26 '17 at 16:27

add a commentÂ |Â

up vote
0
down vote

accepted

With single awk process:

awk '/StartPattern/ f=1;r=""; next f && /EndPattern/f=0
 f r=(r=="")? $0: r RS $0 END print r ' file > output

output file contents:

11
12
13

Alternative tac + awk solution:

tac file | awk '/StartPattern/exit/EndPattern/f=1;nextf' | tac > output

edited Sep 26 '17 at 16:24

answered Sep 26 '17 at 16:05

RomanPerekhrest

22.5k12145

With single awk process:

awk '/StartPattern/ f=1;r=""; next f && /EndPattern/f=0
 f r=(r=="")? $0: r RS $0 END print r ' file > output

output file contents:

11
12
13

Alternative tac + awk solution:

tac file | awk '/StartPattern/exit/EndPattern/f=1;nextf' | tac > output

edited Sep 26 '17 at 16:24

answered Sep 26 '17 at 16:05

RomanPerekhrest

22.5k12145

edited Sep 26 '17 at 16:24

answered Sep 26 '17 at 16:05

RomanPerekhrest

22.5k12145

answered Sep 26 '17 at 16:05

RomanPerekhrest

22.5k12145

answered Sep 26 '17 at 16:05

RomanPerekhrest

22.5k12145

This works if the End Pattern is the last line of the file. I realize my original post (which is now editted) was misleading. How can I only extract what's in between the patterns and not the rest of the file if there are lines below the last EndPattern?
â€“Â A. B
Sep 26 '17 at 16:12

@A.B, it will work even if EndPattern is not the last line. You need to test
â€“Â RomanPerekhrest
Sep 26 '17 at 16:14

Your first answer (tac+awk) prints: 11 12 13 14 15. However, your new answer (single awk) gives the correct output.
â€“Â A. B
Sep 26 '17 at 16:22

@A.B, I can not see the issue. Look here ibb.co/bTqUYk
â€“Â RomanPerekhrest
Sep 26 '17 at 16:27

add a commentÂ |Â

This works if the End Pattern is the last line of the file. I realize my original post (which is now editted) was misleading. How can I only extract what's in between the patterns and not the rest of the file if there are lines below the last EndPattern?
â€“Â A. B
Sep 26 '17 at 16:12

@A.B, it will work even if EndPattern is not the last line. You need to test
â€“Â RomanPerekhrest
Sep 26 '17 at 16:14

Your first answer (tac+awk) prints: 11 12 13 14 15. However, your new answer (single awk) gives the correct output.
â€“Â A. B
Sep 26 '17 at 16:22

@A.B, I can not see the issue. Look here ibb.co/bTqUYk
â€“Â RomanPerekhrest
Sep 26 '17 at 16:27

This works if the End Pattern is the last line of the file. I realize my original post (which is now editted) was misleading. How can I only extract what's in between the patterns and not the rest of the file if there are lines below the last EndPattern?
â€“Â A. B
Sep 26 '17 at 16:12

@A.B, it will work even if EndPattern is not the last line. You need to test
â€“Â RomanPerekhrest
Sep 26 '17 at 16:14

Your first answer (tac+awk) prints: 11 12 13 14 15. However, your new answer (single awk) gives the correct output.
â€“Â A. B
Sep 26 '17 at 16:22

@A.B, I can not see the issue. Look here ibb.co/bTqUYk
â€“Â RomanPerekhrest
Sep 26 '17 at 16:27

add a commentÂ |Â

up vote
0
down vote

cat file |sed -n 'H; /^StartPattern/h; $g;p;' |sed -e '1d' -e '/EndPattern/q' |sed '$ d'

answered Sep 26 '17 at 17:37

Emilio Galarraga

32628

add a commentÂ |Â

up vote
0
down vote

cat file |sed -n 'H; /^StartPattern/h; $g;p;' |sed -e '1d' -e '/EndPattern/q' |sed '$ d'

answered Sep 26 '17 at 17:37

Emilio Galarraga

32628

add a commentÂ |Â

up vote
0
down vote

cat file |sed -n 'H; /^StartPattern/h; $g;p;' |sed -e '1d' -e '/EndPattern/q' |sed '$ d'

answered Sep 26 '17 at 17:37

Emilio Galarraga

32628

cat file |sed -n 'H; /^StartPattern/h; $g;p;' |sed -e '1d' -e '/EndPattern/q' |sed '$ d'

answered Sep 26 '17 at 17:37

Emilio Galarraga

32628

answered Sep 26 '17 at 17:37

Emilio Galarraga

32628

answered Sep 26 '17 at 17:37

Emilio Galarraga

32628

answered Sep 26 '17 at 17:37

Emilio Galarraga

32628

add a commentÂ |Â

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