mjhjmtu

Example:

.
├── f1.md
├── f2.md
├── f3.md
├── f4.txt
├── f5.csv
├── f6.doc
├── s1
├── s2
├── s3
└── s4

4 directories, 6 files

I want to copy f1.md/f2.md/f3.md in current directory, and the results would be t-f1.md/t-f2.md/t-f3.md.(prefix is t-)

Trying and Hope:

for file in *md;do cp -a $file t-$file;done will get result but it seems very long by using for loop. I hope if there is shorter and simple command to get the same results.

The shortest way with GNU parallel:

parallel --no-notice 'cp "" "t-"' ::: *.md

https://www.gnu.org/software/parallel/parallel_tutorial.html

To copy the files the loop you already have is the shortest way to do it. If you want to do it without the loop you could combine cp rename and mv

mkdir tmp
cp -a *.md tmp
(cd tmp && rename '' 't-' tmp/*.md)
mv temp/*.md .

This reduces the commands you have to run (only one cp command vs one for each file), this may or may not make the program faster to run - you would need to benchmark it. But will fail if you have a very large number of files as we pass all of the files to the cp rename and mv.

With mmv / mcp:

mcp '*.md' t-#1.md

Ex. given

$ tree .
.
├── f1.md
├── f2.md
├── f3.md
├── f4.txt
├── f5.csv
├── f6.doc
├── s1
├── s2
├── s3
└── s4

0 directories, 10 files

Then

$ mcp -v '*.md' t-#1.md
f1.md -> t-f1.md : done
f2.md -> t-f2.md : done
f3.md -> t-f3.md : done

resulting in

$ tree .
.
├── f1.md
├── f2.md
├── f3.md
├── f4.txt
├── f5.csv
├── f6.doc
├── s1
├── s2
├── s3
├── s4
├── t-f1.md
├── t-f2.md
└── t-f3.md

0 directories, 13 files