mjhjmtu

I want the new file to have the same name as the new one but with random number in the name.

For example input: sometext.txt, output: sometext_XX.txt and the XX will be a random number each time.

The following code is my attempt but after the tr command it says:

no such directory exists.

#!/bin/bash
END="$#"
i=1
while [ "$i" -le "$END" ]; do
 tr -d ' ' < $temp > "input_XX.txt"
 i=$(($i+1)
done

Maybe something like this:

#!/bin/bash

for filename; do
 base="$filename%.*"
 ext="$filename##*."

 tr -d ' ' < "$filename" > "$base_$RANDOM.$ext"
done

The for filename will loop over all parameters automatically. The base= and ext= lines separate the filename into the basename and the extension. I use $RANDOM for random numbers, so the size of that will be bigger than two digits. Also note that this expects the input files to be in the current working directory – you'd need to do a bit more work to make this for for files in arbitrary directories.

How about just looping over the files? You don’t need to pass them all to the script in one go.

for file in /path/to/files/*.txt ; do mv “$file” “$file%.*”_”$RANDOM”.txt ;done

I can’t test this right now, but there is a bash builtin environment variable ($RANDOM) for just such purposes. AFAIK it should change each time its used (someone please correct me if not).

$RANDOM may need curly braces too for the command to parse correctly, but can’t test it right now as I said.