I'm more than my brother but have less
Clash Royale CLAN TAG#URR8PPP
$begingroup$
We are two brothers
bounded by a circle
I'm his double
but he has twice more legs than me
What are we?
riddle
asked Jan 18 at 9:58
yunzenyunzen
43611
$endgroup$
add a comment |
$begingroup$
We are two brothers
bounded by a circle
I'm his double
but he has twice more legs than me
What are we?
riddle
asked Jan 18 at 9:58
yunzenyunzen
43611
$endgroup$
$begingroup$
This is my first riddle, and if anything should be unclear or two broad, I'd like to apologize for that in advance.
$endgroup$
– yunzen
Jan 18 at 10:03
add a comment |
$begingroup$
We are two brothers
bounded by a circle
I'm his double
but he has twice more legs than me
What are we?
riddle
asked Jan 18 at 9:58
yunzenyunzen
43611
$endgroup$
We are two brothers
bounded by a circle
I'm his double
but he has twice more legs than me
What are we?
riddle
riddle
asked Jan 18 at 9:58
yunzenyunzen
43611
asked Jan 18 at 9:58
yunzenyunzen
43611
asked Jan 18 at 9:58
yunzenyunzen
43611
asked Jan 18 at 9:58
yunzenyunzen
43611
asked Jan 18 at 9:58
yunzenyunzen
43611
43611
$begingroup$
This is my first riddle, and if anything should be unclear or two broad, I'd like to apologize for that in advance.
$endgroup$
– yunzen
Jan 18 at 10:03
add a comment |
$begingroup$
This is my first riddle, and if anything should be unclear or two broad, I'd like to apologize for that in advance.
$endgroup$
– yunzen
Jan 18 at 10:03
$begingroup$
This is my first riddle, and if anything should be unclear or two broad, I'd like to apologize for that in advance.
$endgroup$
– yunzen
Jan 18 at 10:03
$begingroup$
This is my first riddle, and if anything should be unclear or two broad, I'd like to apologize for that in advance.
$endgroup$
– yunzen
Jan 18 at 10:03
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
I think this is a play on something around
pi ($pi$) and tau ($tau$) both circle ratios.
I'm his double but he has twice more legs than me
$tau = 2pi$ but $pi$ has twice the number of legs of $tau$.
answered Jan 18 at 10:07
TomTom
31.9k3109186
$endgroup$
2
$begingroup$
That was even faster than I'm allowed to accept it
$endgroup$
– yunzen
Jan 18 at 10:13
1
$begingroup$
Thanks HerrSerker! I was fortunate as once asked Before the Ides of March
$endgroup$
– Tom
Jan 18 at 10:18
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
return StackExchange.using("mathjaxEditing", function ()
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
);
);
, "mathjax-editing");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "559"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f78568%2fim-more-than-my-brother-but-have-less%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
I think this is a play on something around
pi ($pi$) and tau ($tau$) both circle ratios.
I'm his double but he has twice more legs than me
$tau = 2pi$ but $pi$ has twice the number of legs of $tau$.
answered Jan 18 at 10:07
TomTom
31.9k3109186
$endgroup$
2
$begingroup$
That was even faster than I'm allowed to accept it
$endgroup$
– yunzen
Jan 18 at 10:13
1
$begingroup$
Thanks HerrSerker! I was fortunate as once asked Before the Ides of March
$endgroup$
– Tom
Jan 18 at 10:18
add a comment |
$begingroup$
I think this is a play on something around
pi ($pi$) and tau ($tau$) both circle ratios.
I'm his double but he has twice more legs than me
$tau = 2pi$ but $pi$ has twice the number of legs of $tau$.
answered Jan 18 at 10:07
TomTom
31.9k3109186
$endgroup$
2
$begingroup$
That was even faster than I'm allowed to accept it
$endgroup$
– yunzen
Jan 18 at 10:13
1
$begingroup$
Thanks HerrSerker! I was fortunate as once asked Before the Ides of March
$endgroup$
– Tom
Jan 18 at 10:18
add a comment |
$begingroup$
I think this is a play on something around
pi ($pi$) and tau ($tau$) both circle ratios.
I'm his double but he has twice more legs than me
$tau = 2pi$ but $pi$ has twice the number of legs of $tau$.
answered Jan 18 at 10:07
TomTom
31.9k3109186
$endgroup$
I think this is a play on something around
pi ($pi$) and tau ($tau$) both circle ratios.
I'm his double but he has twice more legs than me
$tau = 2pi$ but $pi$ has twice the number of legs of $tau$.
answered Jan 18 at 10:07
TomTom
31.9k3109186
answered Jan 18 at 10:07
TomTom
31.9k3109186
answered Jan 18 at 10:07
TomTom
31.9k3109186
answered Jan 18 at 10:07
TomTom
31.9k3109186
31.9k3109186
2
$begingroup$
That was even faster than I'm allowed to accept it
$endgroup$
– yunzen
Jan 18 at 10:13
1
$begingroup$
Thanks HerrSerker! I was fortunate as once asked Before the Ides of March
$endgroup$
– Tom
Jan 18 at 10:18
add a comment |
2
$begingroup$
That was even faster than I'm allowed to accept it
$endgroup$
– yunzen
Jan 18 at 10:13
1
$begingroup$
Thanks HerrSerker! I was fortunate as once asked Before the Ides of March
$endgroup$
– Tom
Jan 18 at 10:18
2
2
$begingroup$
That was even faster than I'm allowed to accept it
$endgroup$
– yunzen
Jan 18 at 10:13
$begingroup$
That was even faster than I'm allowed to accept it
$endgroup$
– yunzen
Jan 18 at 10:13
1
1
$begingroup$
Thanks HerrSerker! I was fortunate as once asked Before the Ides of March
$endgroup$
– Tom
Jan 18 at 10:18
$begingroup$
Thanks HerrSerker! I was fortunate as once asked Before the Ides of March
$endgroup$
– Tom
Jan 18 at 10:18
add a comment |
Thanks for contributing an answer to Puzzling Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f78568%2fim-more-than-my-brother-but-have-less%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
This is my first riddle, and if anything should be unclear or two broad, I'd like to apologize for that in advance.
$endgroup$
– yunzen
Jan 18 at 10:03