mjhjmtu

I'm trying to write my own bash script that detects if Debian's release version is less than 9.0

code:

VERSION=$(cat /etc/debian_version)
echo $VERSION

if [ "$VERSION" -lt "9.0" ]; then
 echo "Debian version is less than 9"
else
 echo "Debian version is greater than 9"
fi

but the error i'm receiving is:

./test.sh: line 4: [: 8.2: integer expression expected

basically, $VERSION is a string type, but it's 8.2. I'm trying to make it become 8.2, but as a float. so I can use <= on it.

Try this, I use to compare the float with bc.

VERSION=$(cat /etc/debian_version)
echo $VERSION
if [ "`echo "$VERSION < 9.0" | bc`" -eq 1 ]; then
 echo "Debian version is less than 9"
else
 echo "Debian version is greater than 9"
fi

one-liner using awk

awk 'if ($1 < 9.0) print "Debian version is less than 9"; else if ($1 > 9.0) print "Debian version is greater than 9";' /etc/debian_version

Version there isn't a simple float number and version 1.10 is greater than 1.9. I think that a solution using sort utility, that knows how to handle versions numbers:

check_versions()
 # check_version <reference> <version to check>
 if [[ $1 == $2 ]]; then
 echo 'same'
 else
 low=$(echo -e "$1n$2" 

ref='8.5' # reference version for check

check_versions $ref '8.2' # current version is lower!
check_versions $ref '8.5' # current version is equal!
check_versions $ref '8.12' # current version is greater!

I think that it should a better solution.