mjhjmtu

I need to search (on the whole disk) and replace (where there are matches) one file with another (both in the same path).

Example:

 Folder 1
 x*.txt (good) (e.g.: xFile.txt)
 *.txt (bad) (e.g.: File.txt)

If there is a match of both files in the same path, i need to delete: *.txt (e.g.: File.txt) and rename: x*.txt (e.g.: xFile.txt) to *.txt (e.g.: File.txt)

Result:

 Folder 1
 *.txt (e.g: File.txt... old xFile.txt)

I use this command:

find -name 'x*.txt' | sed -r 'p;s/g([^/]*.txt)/1/' | xargs -d 'n' -n2 mv

The problem is that the command does not verify if both files exist (xFile.txt and File.txt in the same path) before executing the order

How can I solve it? Thanks in advance

With GNU tools, you could do something like:

(export LC_ALL=C
 find . -name '*.txt' -print0 |
 sed -Ez 's|/x([^/]*)$|/1|' |
 sort -z |
 uniq -zd |
 sed -z 'h;s|.*/|&x|;G' |
 xargs -r0n2 echo mv)

That assumes there are not files whose name starts with more than one x. For instance, it won't do mv ./xx.txt ./x.txt

First, we define a function to do the work for us:

switcheroo() 
 [[ -f x"$1" ]] && mv -f x"$1" "$1"

export -f switcheroo

Now, we use find and some black magic to iterate over our foundlings:

find . -name *.txt -execdir bash -c 'switcheroo "$0"' "" ;

We use find to locate all files with a .txt extension (this can be refined to suit whatever criteria you like) and in turn run them through the switcheroo process -- we use [[ ... ]] to test for the existence of the replacement file, and if it is present, use mv to effect the replacement.