simple script rotating table
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3
I'm trying to write a script, that just rotates csv table.
I mean I have some file:
head1;head2;head3
field11;field12;field13
and so on.
All I want, just to make my file
head1;field11;field21
head2;fielad12;field22
head3;field13;field23
I even haven't any idea about how it may work.
I don't ask you to write a script, I need idea about how I can maje it in standart shell (unfortunately I'm not able to use bashism or gnu extensions, POSIX only)
ps. Actually I can do it, but only in ugly way with unbelievable enefficient multirereading file with table. I believe there is more beautiful way.
bash sed awk
edited Mar 18 at 2:03
Rui F Ribeiro
42.1k1484142
asked Mar 26 '12 at 15:08
rushrush
19.6k46696
add a comment |
3
I'm trying to write a script, that just rotates csv table.
I mean I have some file:
head1;head2;head3
field11;field12;field13
and so on.
All I want, just to make my file
head1;field11;field21
head2;fielad12;field22
head3;field13;field23
I even haven't any idea about how it may work.
I don't ask you to write a script, I need idea about how I can maje it in standart shell (unfortunately I'm not able to use bashism or gnu extensions, POSIX only)
ps. Actually I can do it, but only in ugly way with unbelievable enefficient multirereading file with table. I believe there is more beautiful way.
bash sed awk
edited Mar 18 at 2:03
Rui F Ribeiro
42.1k1484142
asked Mar 26 '12 at 15:08
rushrush
19.6k46696
2
Duplicate of stackoverflow.com/questions/1729824/transpose-a-file-in-bash ?
– dying_sphynx
Mar 26 '12 at 15:19
@dying_sphynx Almost... This is a more general case, because the separators make some difference. I gave an example of bash adaptation for semicolons below and let others decide whether the difference is enough to call this question unique.
– rozcietrzewiacz
Mar 26 '12 at 16:16
Actually I just couldn't find this question on SO. It's pretty similar and seems to me the difference in separator isn't enough to make this question unique. Thank you for link on original question.
– rush
Mar 26 '12 at 16:35
add a comment |
3
3
3
I'm trying to write a script, that just rotates csv table.
I mean I have some file:
head1;head2;head3
field11;field12;field13
and so on.
All I want, just to make my file
head1;field11;field21
head2;fielad12;field22
head3;field13;field23
I even haven't any idea about how it may work.
I don't ask you to write a script, I need idea about how I can maje it in standart shell (unfortunately I'm not able to use bashism or gnu extensions, POSIX only)
ps. Actually I can do it, but only in ugly way with unbelievable enefficient multirereading file with table. I believe there is more beautiful way.
bash sed awk
edited Mar 18 at 2:03
Rui F Ribeiro
42.1k1484142
asked Mar 26 '12 at 15:08
rushrush
19.6k46696
I'm trying to write a script, that just rotates csv table.
I mean I have some file:
head1;head2;head3
field11;field12;field13
and so on.
All I want, just to make my file
head1;field11;field21
head2;fielad12;field22
head3;field13;field23
I even haven't any idea about how it may work.
I don't ask you to write a script, I need idea about how I can maje it in standart shell (unfortunately I'm not able to use bashism or gnu extensions, POSIX only)
ps. Actually I can do it, but only in ugly way with unbelievable enefficient multirereading file with table. I believe there is more beautiful way.
bash sed awk
bash sed awk
edited Mar 18 at 2:03
Rui F Ribeiro
42.1k1484142
asked Mar 26 '12 at 15:08
rushrush
19.6k46696
edited Mar 18 at 2:03
Rui F Ribeiro
42.1k1484142
asked Mar 26 '12 at 15:08
rushrush
19.6k46696
edited Mar 18 at 2:03
Rui F Ribeiro
42.1k1484142
edited Mar 18 at 2:03
Rui F Ribeiro
42.1k1484142
edited Mar 18 at 2:03
Rui F Ribeiro
42.1k1484142
42.1k1484142
asked Mar 26 '12 at 15:08
rushrush
19.6k46696
asked Mar 26 '12 at 15:08
rushrush
19.6k46696
asked Mar 26 '12 at 15:08
rushrush
19.6k46696
19.6k46696
2
Duplicate of stackoverflow.com/questions/1729824/transpose-a-file-in-bash ?
– dying_sphynx
Mar 26 '12 at 15:19
@dying_sphynx Almost... This is a more general case, because the separators make some difference. I gave an example of bash adaptation for semicolons below and let others decide whether the difference is enough to call this question unique.
– rozcietrzewiacz
Mar 26 '12 at 16:16
Actually I just couldn't find this question on SO. It's pretty similar and seems to me the difference in separator isn't enough to make this question unique. Thank you for link on original question.
– rush
Mar 26 '12 at 16:35
add a comment |
2
Duplicate of stackoverflow.com/questions/1729824/transpose-a-file-in-bash ?
– dying_sphynx
Mar 26 '12 at 15:19
@dying_sphynx Almost... This is a more general case, because the separators make some difference. I gave an example of bash adaptation for semicolons below and let others decide whether the difference is enough to call this question unique.
– rozcietrzewiacz
Mar 26 '12 at 16:16
Actually I just couldn't find this question on SO. It's pretty similar and seems to me the difference in separator isn't enough to make this question unique. Thank you for link on original question.
– rush
Mar 26 '12 at 16:35
2
2
Duplicate of stackoverflow.com/questions/1729824/transpose-a-file-in-bash ?
– dying_sphynx
Mar 26 '12 at 15:19
Duplicate of stackoverflow.com/questions/1729824/transpose-a-file-in-bash ?
– dying_sphynx
Mar 26 '12 at 15:19
@dying_sphynx Almost... This is a more general case, because the separators make some difference. I gave an example of bash adaptation for semicolons below and let others decide whether the difference is enough to call this question unique.
– rozcietrzewiacz
Mar 26 '12 at 16:16
@dying_sphynx Almost... This is a more general case, because the separators make some difference. I gave an example of bash adaptation for semicolons below and let others decide whether the difference is enough to call this question unique.
– rozcietrzewiacz
Mar 26 '12 at 16:16
Actually I just couldn't find this question on SO. It's pretty similar and seems to me the difference in separator isn't enough to make this question unique. Thank you for link on original question.
– rush
Mar 26 '12 at 16:35
Actually I just couldn't find this question on SO. It's pretty similar and seems to me the difference in separator isn't enough to make this question unique. Thank you for link on original question.
– rush
Mar 26 '12 at 16:35
add a comment |
2 Answers
2
active
oldest
votes
1
Here's a quick adaptation of the bash solution to this similar SO question for the particular separators you have (semicolons):
declare -a array=( ) # we build a 1-D-array
IFS=';' read -a line < "$1" # read the headline
COLS=$#line[@] # save number of columns
index=0
while IFS=';' read -a line ; do
for (( COUNTER=0; COUNTER<$#line[@]; COUNTER++ )); do
array[$index]=$line[$COUNTER]
((index++))
done
done < "$1"
for (( ROW = 0; ROW < COLS; ROW++ )); do
printf "%s" $array[$ROW]
for (( COUNTER = ROW+COLS; COUNTER < $#array[@]; COUNTER += COLS )); do
printf ";%s" $array[$COUNTER]
done
printf "n"
done
edited May 23 '17 at 12:39
Community♦
1
answered Mar 26 '12 at 15:57
rozcietrzewiaczrozcietrzewiacz
29.6k47392
PS. Actually solution with awk that is in SO works much better. But thank you anyway.
– rush
Mar 26 '12 at 18:08
@rush Yes,awkis much faster in this kind of operations. It is definitely worth learning! I myself don't know it well enough yet, so I proposed abashway.
– rozcietrzewiacz
Aug 24 '12 at 15:41
add a comment |
0
flds=3; for((i=1;i<=flds;i++));do
printf '%s' "$(cut -d';' -f$i file)" |tr 'n' ';';echo
done
answered Mar 26 '12 at 17:50
Peter.OPeter.O
19.2k1891146
Thanks, but that's not the solution I'm looking for. In this case I need read file as many times as columns I have. It's useful only for small files. Not my case.
– rush
Mar 26 '12 at 18:07
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
Here's a quick adaptation of the bash solution to this similar SO question for the particular separators you have (semicolons):
declare -a array=( ) # we build a 1-D-array
IFS=';' read -a line < "$1" # read the headline
COLS=$#line[@] # save number of columns
index=0
while IFS=';' read -a line ; do
for (( COUNTER=0; COUNTER<$#line[@]; COUNTER++ )); do
array[$index]=$line[$COUNTER]
((index++))
done
done < "$1"
for (( ROW = 0; ROW < COLS; ROW++ )); do
printf "%s" $array[$ROW]
for (( COUNTER = ROW+COLS; COUNTER < $#array[@]; COUNTER += COLS )); do
printf ";%s" $array[$COUNTER]
done
printf "n"
done
edited May 23 '17 at 12:39
Community♦
1
answered Mar 26 '12 at 15:57
rozcietrzewiaczrozcietrzewiacz
29.6k47392
PS. Actually solution with awk that is in SO works much better. But thank you anyway.
– rush
Mar 26 '12 at 18:08
@rush Yes,awkis much faster in this kind of operations. It is definitely worth learning! I myself don't know it well enough yet, so I proposed abashway.
– rozcietrzewiacz
Aug 24 '12 at 15:41
add a comment |
1
Here's a quick adaptation of the bash solution to this similar SO question for the particular separators you have (semicolons):
declare -a array=( ) # we build a 1-D-array
IFS=';' read -a line < "$1" # read the headline
COLS=$#line[@] # save number of columns
index=0
while IFS=';' read -a line ; do
for (( COUNTER=0; COUNTER<$#line[@]; COUNTER++ )); do
array[$index]=$line[$COUNTER]
((index++))
done
done < "$1"
for (( ROW = 0; ROW < COLS; ROW++ )); do
printf "%s" $array[$ROW]
for (( COUNTER = ROW+COLS; COUNTER < $#array[@]; COUNTER += COLS )); do
printf ";%s" $array[$COUNTER]
done
printf "n"
done
edited May 23 '17 at 12:39
Community♦
1
answered Mar 26 '12 at 15:57
rozcietrzewiaczrozcietrzewiacz
29.6k47392
PS. Actually solution with awk that is in SO works much better. But thank you anyway.
– rush
Mar 26 '12 at 18:08
@rush Yes,awkis much faster in this kind of operations. It is definitely worth learning! I myself don't know it well enough yet, so I proposed abashway.
– rozcietrzewiacz
Aug 24 '12 at 15:41
add a comment |
1
1
1
Here's a quick adaptation of the bash solution to this similar SO question for the particular separators you have (semicolons):
declare -a array=( ) # we build a 1-D-array
IFS=';' read -a line < "$1" # read the headline
COLS=$#line[@] # save number of columns
index=0
while IFS=';' read -a line ; do
for (( COUNTER=0; COUNTER<$#line[@]; COUNTER++ )); do
array[$index]=$line[$COUNTER]
((index++))
done
done < "$1"
for (( ROW = 0; ROW < COLS; ROW++ )); do
printf "%s" $array[$ROW]
for (( COUNTER = ROW+COLS; COUNTER < $#array[@]; COUNTER += COLS )); do
printf ";%s" $array[$COUNTER]
done
printf "n"
done
edited May 23 '17 at 12:39
Community♦
1
answered Mar 26 '12 at 15:57
rozcietrzewiaczrozcietrzewiacz
29.6k47392
Here's a quick adaptation of the bash solution to this similar SO question for the particular separators you have (semicolons):
declare -a array=( ) # we build a 1-D-array
IFS=';' read -a line < "$1" # read the headline
COLS=$#line[@] # save number of columns
index=0
while IFS=';' read -a line ; do
for (( COUNTER=0; COUNTER<$#line[@]; COUNTER++ )); do
array[$index]=$line[$COUNTER]
((index++))
done
done < "$1"
for (( ROW = 0; ROW < COLS; ROW++ )); do
printf "%s" $array[$ROW]
for (( COUNTER = ROW+COLS; COUNTER < $#array[@]; COUNTER += COLS )); do
printf ";%s" $array[$COUNTER]
done
printf "n"
done
edited May 23 '17 at 12:39
Community♦
1
answered Mar 26 '12 at 15:57
rozcietrzewiaczrozcietrzewiacz
29.6k47392
edited May 23 '17 at 12:39
Community♦
1
edited May 23 '17 at 12:39
Community♦
1
edited May 23 '17 at 12:39
Community♦
1
1
answered Mar 26 '12 at 15:57
rozcietrzewiaczrozcietrzewiacz
29.6k47392
answered Mar 26 '12 at 15:57
rozcietrzewiaczrozcietrzewiacz
29.6k47392
answered Mar 26 '12 at 15:57
rozcietrzewiaczrozcietrzewiacz
29.6k47392
29.6k47392
PS. Actually solution with awk that is in SO works much better. But thank you anyway.
– rush
Mar 26 '12 at 18:08
@rush Yes,awkis much faster in this kind of operations. It is definitely worth learning! I myself don't know it well enough yet, so I proposed abashway.
– rozcietrzewiacz
Aug 24 '12 at 15:41
add a comment |
PS. Actually solution with awk that is in SO works much better. But thank you anyway.
– rush
Mar 26 '12 at 18:08
@rush Yes,awkis much faster in this kind of operations. It is definitely worth learning! I myself don't know it well enough yet, so I proposed abashway.
– rozcietrzewiacz
Aug 24 '12 at 15:41
PS. Actually solution with awk that is in SO works much better. But thank you anyway.
– rush
Mar 26 '12 at 18:08
PS. Actually solution with awk that is in SO works much better. But thank you anyway.
– rush
Mar 26 '12 at 18:08
@rush Yes,
awk is much faster in this kind of operations. It is definitely worth learning! I myself don't know it well enough yet, so I proposed a bash way.– rozcietrzewiacz
Aug 24 '12 at 15:41
@rush Yes,
awk is much faster in this kind of operations. It is definitely worth learning! I myself don't know it well enough yet, so I proposed a bash way.– rozcietrzewiacz
Aug 24 '12 at 15:41
add a comment |
0
flds=3; for((i=1;i<=flds;i++));do
printf '%s' "$(cut -d';' -f$i file)" |tr 'n' ';';echo
done
answered Mar 26 '12 at 17:50
Peter.OPeter.O
19.2k1891146
Thanks, but that's not the solution I'm looking for. In this case I need read file as many times as columns I have. It's useful only for small files. Not my case.
– rush
Mar 26 '12 at 18:07
add a comment |
0
flds=3; for((i=1;i<=flds;i++));do
printf '%s' "$(cut -d';' -f$i file)" |tr 'n' ';';echo
done
answered Mar 26 '12 at 17:50
Peter.OPeter.O
19.2k1891146
Thanks, but that's not the solution I'm looking for. In this case I need read file as many times as columns I have. It's useful only for small files. Not my case.
– rush
Mar 26 '12 at 18:07
add a comment |
0
0
0
flds=3; for((i=1;i<=flds;i++));do
printf '%s' "$(cut -d';' -f$i file)" |tr 'n' ';';echo
done
answered Mar 26 '12 at 17:50
Peter.OPeter.O
19.2k1891146
flds=3; for((i=1;i<=flds;i++));do
printf '%s' "$(cut -d';' -f$i file)" |tr 'n' ';';echo
done
answered Mar 26 '12 at 17:50
Peter.OPeter.O
19.2k1891146
answered Mar 26 '12 at 17:50
Peter.OPeter.O
19.2k1891146
answered Mar 26 '12 at 17:50
Peter.OPeter.O
19.2k1891146
answered Mar 26 '12 at 17:50
Peter.OPeter.O
19.2k1891146
19.2k1891146
Thanks, but that's not the solution I'm looking for. In this case I need read file as many times as columns I have. It's useful only for small files. Not my case.
– rush
Mar 26 '12 at 18:07
add a comment |
Thanks, but that's not the solution I'm looking for. In this case I need read file as many times as columns I have. It's useful only for small files. Not my case.
– rush
Mar 26 '12 at 18:07
Thanks, but that's not the solution I'm looking for. In this case I need read file as many times as columns I have. It's useful only for small files. Not my case.
– rush
Mar 26 '12 at 18:07
Thanks, but that's not the solution I'm looking for. In this case I need read file as many times as columns I have. It's useful only for small files. Not my case.
– rush
Mar 26 '12 at 18:07
add a comment |
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2
Duplicate of stackoverflow.com/questions/1729824/transpose-a-file-in-bash ?
– dying_sphynx
Mar 26 '12 at 15:19
@dying_sphynx Almost... This is a more general case, because the separators make some difference. I gave an example of bash adaptation for semicolons below and let others decide whether the difference is enough to call this question unique.
– rozcietrzewiacz
Mar 26 '12 at 16:16
Actually I just couldn't find this question on SO. It's pretty similar and seems to me the difference in separator isn't enough to make this question unique. Thank you for link on original question.
– rush
Mar 26 '12 at 16:35