Remove legend if a plot in an array of plots is empty
Clash Royale CLAN TAG#URR8PPP
In an array of plots of regions (inequalities) p[..] which are eventually combined using Show, how do I suppress the legend of plots which are empty, and look like this
More generally, if in a given range of $x$ and $y$ over which a region is prescribed to be plotted, if RegionPlot does not find a solution (so that there is no region to shade or fill), is there a way to get a True or False value from RegionPlot corresponding to whether the region exists or not?
plotting regions legending inequalities
asked Dec 22 '18 at 22:07
leastaction
20529
add a comment |
In an array of plots of regions (inequalities) p[..] which are eventually combined using Show, how do I suppress the legend of plots which are empty, and look like this
More generally, if in a given range of $x$ and $y$ over which a region is prescribed to be plotted, if RegionPlot does not find a solution (so that there is no region to shade or fill), is there a way to get a True or False value from RegionPlot corresponding to whether the region exists or not?
plotting regions legending inequalities
asked Dec 22 '18 at 22:07
leastaction
20529
add a comment |
In an array of plots of regions (inequalities) p[..] which are eventually combined using Show, how do I suppress the legend of plots which are empty, and look like this
More generally, if in a given range of $x$ and $y$ over which a region is prescribed to be plotted, if RegionPlot does not find a solution (so that there is no region to shade or fill), is there a way to get a True or False value from RegionPlot corresponding to whether the region exists or not?
plotting regions legending inequalities
asked Dec 22 '18 at 22:07
leastaction
20529
In an array of plots of regions (inequalities) p[..] which are eventually combined using Show, how do I suppress the legend of plots which are empty, and look like this
More generally, if in a given range of $x$ and $y$ over which a region is prescribed to be plotted, if RegionPlot does not find a solution (so that there is no region to shade or fill), is there a way to get a True or False value from RegionPlot corresponding to whether the region exists or not?
plotting regions legending inequalities
plotting regions legending inequalities
asked Dec 22 '18 at 22:07
leastaction
20529
asked Dec 22 '18 at 22:07
leastaction
20529
asked Dec 22 '18 at 22:07
leastaction
20529
asked Dec 22 '18 at 22:07
leastaction
20529
asked Dec 22 '18 at 22:07
leastaction
20529
20529
add a comment |
add a comment |
2 Answers
2
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votes
You can express the region using ImplicitRegion and then plot it or check the area of the region. Example:
reg = ImplicitRegion[x^2 + y^3 < 2, x, -2, 2, y, -2, 2];
RegionPlot[reg]
Chop@N@Area[reg]
9.91915
Checking to see if the area of the region is nonzero:
If[Chop@N@Area[reg] > 0, ...]
answered Dec 22 '18 at 22:48
C. E.
50k397202
add a comment |
colors = RotateLeft[ColorData[97] /@ 1, 2, 3];
regs = x^2 < (y - 2)^3 + 1, (y + 2)^2 < (x - 2)^3 + 1, x + y <= -2;
Show[With[col = First[colors = RotateRight[colors]],
RegionPlot[#, x, -5, 5, y, -5, 5, PlotStyle -> col,
PlotLegends -> If[Area[ImplicitRegion[#, x, -5, 5, y, -5, 5]] === 0, None, #],
PlotRange -> -5, 5, -5, 5]] & /@ (And[#, True] & /@ regs)]
Replace And[#, True] & with And[#, x >= 2 y] & to get
Replace And[#, True] & with And[#, x <= y] & to get
answered Dec 23 '18 at 0:28
kglr
177k9198406
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can express the region using ImplicitRegion and then plot it or check the area of the region. Example:
reg = ImplicitRegion[x^2 + y^3 < 2, x, -2, 2, y, -2, 2];
RegionPlot[reg]
Chop@N@Area[reg]
9.91915
Checking to see if the area of the region is nonzero:
If[Chop@N@Area[reg] > 0, ...]
answered Dec 22 '18 at 22:48
C. E.
50k397202
add a comment |
You can express the region using ImplicitRegion and then plot it or check the area of the region. Example:
reg = ImplicitRegion[x^2 + y^3 < 2, x, -2, 2, y, -2, 2];
RegionPlot[reg]
Chop@N@Area[reg]
9.91915
Checking to see if the area of the region is nonzero:
If[Chop@N@Area[reg] > 0, ...]
answered Dec 22 '18 at 22:48
C. E.
50k397202
add a comment |
You can express the region using ImplicitRegion and then plot it or check the area of the region. Example:
reg = ImplicitRegion[x^2 + y^3 < 2, x, -2, 2, y, -2, 2];
RegionPlot[reg]
Chop@N@Area[reg]
9.91915
Checking to see if the area of the region is nonzero:
If[Chop@N@Area[reg] > 0, ...]
answered Dec 22 '18 at 22:48
C. E.
50k397202
You can express the region using ImplicitRegion and then plot it or check the area of the region. Example:
reg = ImplicitRegion[x^2 + y^3 < 2, x, -2, 2, y, -2, 2];
RegionPlot[reg]
Chop@N@Area[reg]
9.91915
Checking to see if the area of the region is nonzero:
If[Chop@N@Area[reg] > 0, ...]
answered Dec 22 '18 at 22:48
C. E.
50k397202
answered Dec 22 '18 at 22:48
C. E.
50k397202
answered Dec 22 '18 at 22:48
C. E.
50k397202
answered Dec 22 '18 at 22:48
C. E.
50k397202
50k397202
add a comment |
add a comment |
colors = RotateLeft[ColorData[97] /@ 1, 2, 3];
regs = x^2 < (y - 2)^3 + 1, (y + 2)^2 < (x - 2)^3 + 1, x + y <= -2;
Show[With[col = First[colors = RotateRight[colors]],
RegionPlot[#, x, -5, 5, y, -5, 5, PlotStyle -> col,
PlotLegends -> If[Area[ImplicitRegion[#, x, -5, 5, y, -5, 5]] === 0, None, #],
PlotRange -> -5, 5, -5, 5]] & /@ (And[#, True] & /@ regs)]
Replace And[#, True] & with And[#, x >= 2 y] & to get
Replace And[#, True] & with And[#, x <= y] & to get
answered Dec 23 '18 at 0:28
kglr
177k9198406
add a comment |
colors = RotateLeft[ColorData[97] /@ 1, 2, 3];
regs = x^2 < (y - 2)^3 + 1, (y + 2)^2 < (x - 2)^3 + 1, x + y <= -2;
Show[With[col = First[colors = RotateRight[colors]],
RegionPlot[#, x, -5, 5, y, -5, 5, PlotStyle -> col,
PlotLegends -> If[Area[ImplicitRegion[#, x, -5, 5, y, -5, 5]] === 0, None, #],
PlotRange -> -5, 5, -5, 5]] & /@ (And[#, True] & /@ regs)]
Replace And[#, True] & with And[#, x >= 2 y] & to get
Replace And[#, True] & with And[#, x <= y] & to get
answered Dec 23 '18 at 0:28
kglr
177k9198406
add a comment |
colors = RotateLeft[ColorData[97] /@ 1, 2, 3];
regs = x^2 < (y - 2)^3 + 1, (y + 2)^2 < (x - 2)^3 + 1, x + y <= -2;
Show[With[col = First[colors = RotateRight[colors]],
RegionPlot[#, x, -5, 5, y, -5, 5, PlotStyle -> col,
PlotLegends -> If[Area[ImplicitRegion[#, x, -5, 5, y, -5, 5]] === 0, None, #],
PlotRange -> -5, 5, -5, 5]] & /@ (And[#, True] & /@ regs)]
Replace And[#, True] & with And[#, x >= 2 y] & to get
Replace And[#, True] & with And[#, x <= y] & to get
answered Dec 23 '18 at 0:28
kglr
177k9198406
colors = RotateLeft[ColorData[97] /@ 1, 2, 3];
regs = x^2 < (y - 2)^3 + 1, (y + 2)^2 < (x - 2)^3 + 1, x + y <= -2;
Show[With[col = First[colors = RotateRight[colors]],
RegionPlot[#, x, -5, 5, y, -5, 5, PlotStyle -> col,
PlotLegends -> If[Area[ImplicitRegion[#, x, -5, 5, y, -5, 5]] === 0, None, #],
PlotRange -> -5, 5, -5, 5]] & /@ (And[#, True] & /@ regs)]
Replace And[#, True] & with And[#, x >= 2 y] & to get
Replace And[#, True] & with And[#, x <= y] & to get
answered Dec 23 '18 at 0:28
kglr
177k9198406
answered Dec 23 '18 at 0:28
kglr
177k9198406
answered Dec 23 '18 at 0:28
kglr
177k9198406
answered Dec 23 '18 at 0:28
kglr
177k9198406
177k9198406
add a comment |
add a comment |
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