BASH script: declare a variable inside CASE statement to use globally

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case $location in
ColocationOne)
# Define MOSES LAKE workerarray
server[0]=serverone
server[1]=servertwo
esac

echo $server[0]


How do I get this to echo: serverone
?










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  • @Peschke I am echoing $server[0] after my initial edit. The first was a typo. I am just trying to use a variable that I declared inside the case statement from outside the case statement.
    – stone212
    Dec 4 at 7:54














up vote
0
down vote

favorite












case $location in
ColocationOne)
# Define MOSES LAKE workerarray
server[0]=serverone
server[1]=servertwo
esac

echo $server[0]


How do I get this to echo: serverone
?










share|improve this question























  • @Peschke I am echoing $server[0] after my initial edit. The first was a typo. I am just trying to use a variable that I declared inside the case statement from outside the case statement.
    – stone212
    Dec 4 at 7:54












up vote
0
down vote

favorite









up vote
0
down vote

favorite











case $location in
ColocationOne)
# Define MOSES LAKE workerarray
server[0]=serverone
server[1]=servertwo
esac

echo $server[0]


How do I get this to echo: serverone
?










share|improve this question















case $location in
ColocationOne)
# Define MOSES LAKE workerarray
server[0]=serverone
server[1]=servertwo
esac

echo $server[0]


How do I get this to echo: serverone
?







bash shell-script variable






share|improve this question















share|improve this question













share|improve this question




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edited Dec 4 at 7:39

























asked Dec 4 at 7:33









stone212

176112




176112











  • @Peschke I am echoing $server[0] after my initial edit. The first was a typo. I am just trying to use a variable that I declared inside the case statement from outside the case statement.
    – stone212
    Dec 4 at 7:54
















  • @Peschke I am echoing $server[0] after my initial edit. The first was a typo. I am just trying to use a variable that I declared inside the case statement from outside the case statement.
    – stone212
    Dec 4 at 7:54















@Peschke I am echoing $server[0] after my initial edit. The first was a typo. I am just trying to use a variable that I declared inside the case statement from outside the case statement.
– stone212
Dec 4 at 7:54




@Peschke I am echoing $server[0] after my initial edit. The first was a typo. I am just trying to use a variable that I declared inside the case statement from outside the case statement.
– stone212
Dec 4 at 7:54










1 Answer
1






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oldest

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up vote
3
down vote



accepted










You set location to the string ColocationOne:



#!/bin/bash

location=ColocationOne

case $location in
ColocationOne)
# Define MOSES LAKE workerarray
server[0]=serverone
server[1]=servertwo
# or: server=( serverone servertwo )
esac

echo "$server[0]"


This script would print serverone.






share|improve this answer
















  • 1




    yes you are correct. My actual script has the quotes. My actual script referenced server[1]. My actual script had server[1] commented out. stone212 is very tired. Thank you.
    – stone212
    Dec 4 at 7:58











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
3
down vote



accepted










You set location to the string ColocationOne:



#!/bin/bash

location=ColocationOne

case $location in
ColocationOne)
# Define MOSES LAKE workerarray
server[0]=serverone
server[1]=servertwo
# or: server=( serverone servertwo )
esac

echo "$server[0]"


This script would print serverone.






share|improve this answer
















  • 1




    yes you are correct. My actual script has the quotes. My actual script referenced server[1]. My actual script had server[1] commented out. stone212 is very tired. Thank you.
    – stone212
    Dec 4 at 7:58















up vote
3
down vote



accepted










You set location to the string ColocationOne:



#!/bin/bash

location=ColocationOne

case $location in
ColocationOne)
# Define MOSES LAKE workerarray
server[0]=serverone
server[1]=servertwo
# or: server=( serverone servertwo )
esac

echo "$server[0]"


This script would print serverone.






share|improve this answer
















  • 1




    yes you are correct. My actual script has the quotes. My actual script referenced server[1]. My actual script had server[1] commented out. stone212 is very tired. Thank you.
    – stone212
    Dec 4 at 7:58













up vote
3
down vote



accepted







up vote
3
down vote



accepted






You set location to the string ColocationOne:



#!/bin/bash

location=ColocationOne

case $location in
ColocationOne)
# Define MOSES LAKE workerarray
server[0]=serverone
server[1]=servertwo
# or: server=( serverone servertwo )
esac

echo "$server[0]"


This script would print serverone.






share|improve this answer












You set location to the string ColocationOne:



#!/bin/bash

location=ColocationOne

case $location in
ColocationOne)
# Define MOSES LAKE workerarray
server[0]=serverone
server[1]=servertwo
# or: server=( serverone servertwo )
esac

echo "$server[0]"


This script would print serverone.







share|improve this answer












share|improve this answer



share|improve this answer










answered Dec 4 at 7:42









Kusalananda

119k16225367




119k16225367







  • 1




    yes you are correct. My actual script has the quotes. My actual script referenced server[1]. My actual script had server[1] commented out. stone212 is very tired. Thank you.
    – stone212
    Dec 4 at 7:58













  • 1




    yes you are correct. My actual script has the quotes. My actual script referenced server[1]. My actual script had server[1] commented out. stone212 is very tired. Thank you.
    – stone212
    Dec 4 at 7:58








1




1




yes you are correct. My actual script has the quotes. My actual script referenced server[1]. My actual script had server[1] commented out. stone212 is very tired. Thank you.
– stone212
Dec 4 at 7:58





yes you are correct. My actual script has the quotes. My actual script referenced server[1]. My actual script had server[1] commented out. stone212 is very tired. Thank you.
– stone212
Dec 4 at 7:58


















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