How can I write a shell script to filter the last command?

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I want to write a script for login statistics. I want to count how many times a user logged in, and then display them in ascending, or descending order, given by the end user. The problme being, i don't know how to write a script that could count how many times a user logged in. I have to use the last command.










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  • 3




    Can't you do last $username for every user, and count the lines being returned? You will have to truncate the last 2 ones though. Also, be warned that the wtmp file only holds records for a specific timeframe.
    – Panki
    Nov 19 at 16:16










  • #!/bin/bash echo '1 - ascending, 0 - descending, please choose:' read x echo 'how many lines do you need?:' read y if [ $x -eq 1 ]; then echo last >> last.txt fi after I have the last.txt file, i need to count how many times one user logged in, then put the data in ascending/descending order. At the end, I have to display A certain amount of lines, strating from 1. Can't really figure out how to do it..
    – Bakos Dominik
    Nov 19 at 16:38















up vote
0
down vote

favorite












I want to write a script for login statistics. I want to count how many times a user logged in, and then display them in ascending, or descending order, given by the end user. The problme being, i don't know how to write a script that could count how many times a user logged in. I have to use the last command.










share|improve this question









New contributor




Bakos Dominik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.















  • 3




    Can't you do last $username for every user, and count the lines being returned? You will have to truncate the last 2 ones though. Also, be warned that the wtmp file only holds records for a specific timeframe.
    – Panki
    Nov 19 at 16:16










  • #!/bin/bash echo '1 - ascending, 0 - descending, please choose:' read x echo 'how many lines do you need?:' read y if [ $x -eq 1 ]; then echo last >> last.txt fi after I have the last.txt file, i need to count how many times one user logged in, then put the data in ascending/descending order. At the end, I have to display A certain amount of lines, strating from 1. Can't really figure out how to do it..
    – Bakos Dominik
    Nov 19 at 16:38













up vote
0
down vote

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up vote
0
down vote

favorite











I want to write a script for login statistics. I want to count how many times a user logged in, and then display them in ascending, or descending order, given by the end user. The problme being, i don't know how to write a script that could count how many times a user logged in. I have to use the last command.










share|improve this question









New contributor




Bakos Dominik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I want to write a script for login statistics. I want to count how many times a user logged in, and then display them in ascending, or descending order, given by the end user. The problme being, i don't know how to write a script that could count how many times a user logged in. I have to use the last command.







shell grep scripting last






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edited 2 days ago









Rui F Ribeiro

38.2k1475125




38.2k1475125






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asked Nov 19 at 16:08









Bakos Dominik

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152




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Bakos Dominik is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






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  • 3




    Can't you do last $username for every user, and count the lines being returned? You will have to truncate the last 2 ones though. Also, be warned that the wtmp file only holds records for a specific timeframe.
    – Panki
    Nov 19 at 16:16










  • #!/bin/bash echo '1 - ascending, 0 - descending, please choose:' read x echo 'how many lines do you need?:' read y if [ $x -eq 1 ]; then echo last >> last.txt fi after I have the last.txt file, i need to count how many times one user logged in, then put the data in ascending/descending order. At the end, I have to display A certain amount of lines, strating from 1. Can't really figure out how to do it..
    – Bakos Dominik
    Nov 19 at 16:38













  • 3




    Can't you do last $username for every user, and count the lines being returned? You will have to truncate the last 2 ones though. Also, be warned that the wtmp file only holds records for a specific timeframe.
    – Panki
    Nov 19 at 16:16










  • #!/bin/bash echo '1 - ascending, 0 - descending, please choose:' read x echo 'how many lines do you need?:' read y if [ $x -eq 1 ]; then echo last >> last.txt fi after I have the last.txt file, i need to count how many times one user logged in, then put the data in ascending/descending order. At the end, I have to display A certain amount of lines, strating from 1. Can't really figure out how to do it..
    – Bakos Dominik
    Nov 19 at 16:38








3




3




Can't you do last $username for every user, and count the lines being returned? You will have to truncate the last 2 ones though. Also, be warned that the wtmp file only holds records for a specific timeframe.
– Panki
Nov 19 at 16:16




Can't you do last $username for every user, and count the lines being returned? You will have to truncate the last 2 ones though. Also, be warned that the wtmp file only holds records for a specific timeframe.
– Panki
Nov 19 at 16:16












#!/bin/bash echo '1 - ascending, 0 - descending, please choose:' read x echo 'how many lines do you need?:' read y if [ $x -eq 1 ]; then echo last >> last.txt fi after I have the last.txt file, i need to count how many times one user logged in, then put the data in ascending/descending order. At the end, I have to display A certain amount of lines, strating from 1. Can't really figure out how to do it..
– Bakos Dominik
Nov 19 at 16:38





#!/bin/bash echo '1 - ascending, 0 - descending, please choose:' read x echo 'how many lines do you need?:' read y if [ $x -eq 1 ]; then echo last >> last.txt fi after I have the last.txt file, i need to count how many times one user logged in, then put the data in ascending/descending order. At the end, I have to display A certain amount of lines, strating from 1. Can't really figure out how to do it..
– Bakos Dominik
Nov 19 at 16:38











1 Answer
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#!/bin/bash
userlist=$(cat /etc/passwd | cut -d : -f 1)
for user in $userlist; do
timesloggedin=$(last $user | head -n -2 | wc -l);
echo $timesloggedin $user;
done | sort -r


This gets the name of ALL the users on the system, including daemon accounts etc.
If you don't want that, supply userlist with a list of your usernames.
To get the output in ascending order, drop the -r flag to sort.






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    1 Answer
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    1 Answer
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    up vote
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    #!/bin/bash
    userlist=$(cat /etc/passwd | cut -d : -f 1)
    for user in $userlist; do
    timesloggedin=$(last $user | head -n -2 | wc -l);
    echo $timesloggedin $user;
    done | sort -r


    This gets the name of ALL the users on the system, including daemon accounts etc.
    If you don't want that, supply userlist with a list of your usernames.
    To get the output in ascending order, drop the -r flag to sort.






    share|improve this answer
























      up vote
      0
      down vote



      accepted










      #!/bin/bash
      userlist=$(cat /etc/passwd | cut -d : -f 1)
      for user in $userlist; do
      timesloggedin=$(last $user | head -n -2 | wc -l);
      echo $timesloggedin $user;
      done | sort -r


      This gets the name of ALL the users on the system, including daemon accounts etc.
      If you don't want that, supply userlist with a list of your usernames.
      To get the output in ascending order, drop the -r flag to sort.






      share|improve this answer






















        up vote
        0
        down vote



        accepted







        up vote
        0
        down vote



        accepted






        #!/bin/bash
        userlist=$(cat /etc/passwd | cut -d : -f 1)
        for user in $userlist; do
        timesloggedin=$(last $user | head -n -2 | wc -l);
        echo $timesloggedin $user;
        done | sort -r


        This gets the name of ALL the users on the system, including daemon accounts etc.
        If you don't want that, supply userlist with a list of your usernames.
        To get the output in ascending order, drop the -r flag to sort.






        share|improve this answer












        #!/bin/bash
        userlist=$(cat /etc/passwd | cut -d : -f 1)
        for user in $userlist; do
        timesloggedin=$(last $user | head -n -2 | wc -l);
        echo $timesloggedin $user;
        done | sort -r


        This gets the name of ALL the users on the system, including daemon accounts etc.
        If you don't want that, supply userlist with a list of your usernames.
        To get the output in ascending order, drop the -r flag to sort.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 20 at 8:54









        Panki

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