What happens to the old stack, heap, and (initialized and uninitialized) data segments after execve() call?

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Manpage of execve() says




execve() executes the program pointed to by filename. This causes
the program that is currently being run by the calling process to be
replaced with a new program, with newly initialized stack, heap, and
(initialized and uninitialized) data segments.




What normally happens to the old "stack, heap, and (initialized and uninitialized) data segments"?



Are they deallocated if the calling process was not created by vfork()?



Before seeing the quote, I thought that execve() would overwrite the old "stack, heap, and (initialized and uninitialized) data segments". So I was surprised to see the quote, and wonder why waste the new space?



Thanks.






linux process exec






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    Manpage of execve() says




    execve() executes the program pointed to by filename. This causes
    the program that is currently being run by the calling process to be
    replaced with a new program, with newly initialized stack, heap, and
    (initialized and uninitialized) data segments.




    What normally happens to the old "stack, heap, and (initialized and uninitialized) data segments"?



    Are they deallocated if the calling process was not created by vfork()?



    Before seeing the quote, I thought that execve() would overwrite the old "stack, heap, and (initialized and uninitialized) data segments". So I was surprised to see the quote, and wonder why waste the new space?



    Thanks.






    linux process exec






    share























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      Manpage of execve() says




      execve() executes the program pointed to by filename. This causes
      the program that is currently being run by the calling process to be
      replaced with a new program, with newly initialized stack, heap, and
      (initialized and uninitialized) data segments.




      What normally happens to the old "stack, heap, and (initialized and uninitialized) data segments"?



      Are they deallocated if the calling process was not created by vfork()?



      Before seeing the quote, I thought that execve() would overwrite the old "stack, heap, and (initialized and uninitialized) data segments". So I was surprised to see the quote, and wonder why waste the new space?



      Thanks.






      linux process exec






      share













      Manpage of execve() says




      execve() executes the program pointed to by filename. This causes
      the program that is currently being run by the calling process to be
      replaced with a new program, with newly initialized stack, heap, and
      (initialized and uninitialized) data segments.




      What normally happens to the old "stack, heap, and (initialized and uninitialized) data segments"?



      Are they deallocated if the calling process was not created by vfork()?



      Before seeing the quote, I thought that execve() would overwrite the old "stack, heap, and (initialized and uninitialized) data segments". So I was surprised to see the quote, and wonder why waste the new space?



      Thanks.






      linux process exec




      linux process exec





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