Q: Using Grep to find a word that contains each of the vowels in the correct order [duplicate]

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  • find words with all vowels in order from a file

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  • grep to find words with all vowels

    3 answers



As the question states above. I'm trying to find out on how to use grep command to find the number of vowels in each word in the correct order in the word file on the root user. I've tried grep -Ew "*[aeiou]*" words But, it never gave me the number of how many such words are there. I need help.










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marked as duplicate by Goro, Jeff Schaller, Community♦ 8 hours ago


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.














  • @msp9011 sure, you want the file? The file is 'words' it's located in the root directory, and I'm trying to find the number of vowels in each word in the correct order in that file.
    – Anonymous
    8 hours ago










  • It's not clear what you want; is it something like perl -nle 'my %k; $k$_++ for m/[aeiou]/g; print $_, map " $_:".($k$_+0), qw(a e i o u)' /usr/share/dict/words ?
    – mosvy
    8 hours ago











  • .. or grep '.*a.*e.*i.*o.*u' /usr/share/dict/words=> abstemious, adventitious, facetious, ..., sacrilegious?
    – mosvy
    8 hours ago










  • @msp9011 Okay here it is but, couldn't ctrl c very quickly to stop it. berserker berserks Bersiamite Bersil bersim berskin berstel Berstine BERT Bert Berta Bertasi Bertat
    – Anonymous
    8 hours ago










  • @mosvy 2nd one yes, but, I'm trying to use grep on words to find a word that contains each of the vowels in the correct order. To find how many such words are there. It's in /root/words I'll try that grep '.*a.*e.*i.*o.*u' /usr/share/dict/words
    – Anonymous
    8 hours ago















up vote
0
down vote

favorite













This question already has an answer here:



  • find words with all vowels in order from a file

    1 answer



  • grep to find words with all vowels

    3 answers



As the question states above. I'm trying to find out on how to use grep command to find the number of vowels in each word in the correct order in the word file on the root user. I've tried grep -Ew "*[aeiou]*" words But, it never gave me the number of how many such words are there. I need help.










share|improve this question















marked as duplicate by Goro, Jeff Schaller, Community♦ 8 hours ago


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.














  • @msp9011 sure, you want the file? The file is 'words' it's located in the root directory, and I'm trying to find the number of vowels in each word in the correct order in that file.
    – Anonymous
    8 hours ago










  • It's not clear what you want; is it something like perl -nle 'my %k; $k$_++ for m/[aeiou]/g; print $_, map " $_:".($k$_+0), qw(a e i o u)' /usr/share/dict/words ?
    – mosvy
    8 hours ago











  • .. or grep '.*a.*e.*i.*o.*u' /usr/share/dict/words=> abstemious, adventitious, facetious, ..., sacrilegious?
    – mosvy
    8 hours ago










  • @msp9011 Okay here it is but, couldn't ctrl c very quickly to stop it. berserker berserks Bersiamite Bersil bersim berskin berstel Berstine BERT Bert Berta Bertasi Bertat
    – Anonymous
    8 hours ago










  • @mosvy 2nd one yes, but, I'm trying to use grep on words to find a word that contains each of the vowels in the correct order. To find how many such words are there. It's in /root/words I'll try that grep '.*a.*e.*i.*o.*u' /usr/share/dict/words
    – Anonymous
    8 hours ago













up vote
0
down vote

favorite









up vote
0
down vote

favorite












This question already has an answer here:



  • find words with all vowels in order from a file

    1 answer



  • grep to find words with all vowels

    3 answers



As the question states above. I'm trying to find out on how to use grep command to find the number of vowels in each word in the correct order in the word file on the root user. I've tried grep -Ew "*[aeiou]*" words But, it never gave me the number of how many such words are there. I need help.










share|improve this question
















This question already has an answer here:



  • find words with all vowels in order from a file

    1 answer



  • grep to find words with all vowels

    3 answers



As the question states above. I'm trying to find out on how to use grep command to find the number of vowels in each word in the correct order in the word file on the root user. I've tried grep -Ew "*[aeiou]*" words But, it never gave me the number of how many such words are there. I need help.





This question already has an answer here:



  • find words with all vowels in order from a file

    1 answer



  • grep to find words with all vowels

    3 answers







linux grep






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share|improve this question













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share|improve this question








edited 8 hours ago









Jeff Schaller

33.8k851113




33.8k851113










asked 8 hours ago









Anonymous

155




155




marked as duplicate by Goro, Jeff Schaller, Community♦ 8 hours ago


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.






marked as duplicate by Goro, Jeff Schaller, Community♦ 8 hours ago


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.













  • @msp9011 sure, you want the file? The file is 'words' it's located in the root directory, and I'm trying to find the number of vowels in each word in the correct order in that file.
    – Anonymous
    8 hours ago










  • It's not clear what you want; is it something like perl -nle 'my %k; $k$_++ for m/[aeiou]/g; print $_, map " $_:".($k$_+0), qw(a e i o u)' /usr/share/dict/words ?
    – mosvy
    8 hours ago











  • .. or grep '.*a.*e.*i.*o.*u' /usr/share/dict/words=> abstemious, adventitious, facetious, ..., sacrilegious?
    – mosvy
    8 hours ago










  • @msp9011 Okay here it is but, couldn't ctrl c very quickly to stop it. berserker berserks Bersiamite Bersil bersim berskin berstel Berstine BERT Bert Berta Bertasi Bertat
    – Anonymous
    8 hours ago










  • @mosvy 2nd one yes, but, I'm trying to use grep on words to find a word that contains each of the vowels in the correct order. To find how many such words are there. It's in /root/words I'll try that grep '.*a.*e.*i.*o.*u' /usr/share/dict/words
    – Anonymous
    8 hours ago

















  • @msp9011 sure, you want the file? The file is 'words' it's located in the root directory, and I'm trying to find the number of vowels in each word in the correct order in that file.
    – Anonymous
    8 hours ago










  • It's not clear what you want; is it something like perl -nle 'my %k; $k$_++ for m/[aeiou]/g; print $_, map " $_:".($k$_+0), qw(a e i o u)' /usr/share/dict/words ?
    – mosvy
    8 hours ago











  • .. or grep '.*a.*e.*i.*o.*u' /usr/share/dict/words=> abstemious, adventitious, facetious, ..., sacrilegious?
    – mosvy
    8 hours ago










  • @msp9011 Okay here it is but, couldn't ctrl c very quickly to stop it. berserker berserks Bersiamite Bersil bersim berskin berstel Berstine BERT Bert Berta Bertasi Bertat
    – Anonymous
    8 hours ago










  • @mosvy 2nd one yes, but, I'm trying to use grep on words to find a word that contains each of the vowels in the correct order. To find how many such words are there. It's in /root/words I'll try that grep '.*a.*e.*i.*o.*u' /usr/share/dict/words
    – Anonymous
    8 hours ago
















@msp9011 sure, you want the file? The file is 'words' it's located in the root directory, and I'm trying to find the number of vowels in each word in the correct order in that file.
– Anonymous
8 hours ago




@msp9011 sure, you want the file? The file is 'words' it's located in the root directory, and I'm trying to find the number of vowels in each word in the correct order in that file.
– Anonymous
8 hours ago












It's not clear what you want; is it something like perl -nle 'my %k; $k$_++ for m/[aeiou]/g; print $_, map " $_:".($k$_+0), qw(a e i o u)' /usr/share/dict/words ?
– mosvy
8 hours ago





It's not clear what you want; is it something like perl -nle 'my %k; $k$_++ for m/[aeiou]/g; print $_, map " $_:".($k$_+0), qw(a e i o u)' /usr/share/dict/words ?
– mosvy
8 hours ago













.. or grep '.*a.*e.*i.*o.*u' /usr/share/dict/words=> abstemious, adventitious, facetious, ..., sacrilegious?
– mosvy
8 hours ago




.. or grep '.*a.*e.*i.*o.*u' /usr/share/dict/words=> abstemious, adventitious, facetious, ..., sacrilegious?
– mosvy
8 hours ago












@msp9011 Okay here it is but, couldn't ctrl c very quickly to stop it. berserker berserks Bersiamite Bersil bersim berskin berstel Berstine BERT Bert Berta Bertasi Bertat
– Anonymous
8 hours ago




@msp9011 Okay here it is but, couldn't ctrl c very quickly to stop it. berserker berserks Bersiamite Bersil bersim berskin berstel Berstine BERT Bert Berta Bertasi Bertat
– Anonymous
8 hours ago












@mosvy 2nd one yes, but, I'm trying to use grep on words to find a word that contains each of the vowels in the correct order. To find how many such words are there. It's in /root/words I'll try that grep '.*a.*e.*i.*o.*u' /usr/share/dict/words
– Anonymous
8 hours ago





@mosvy 2nd one yes, but, I'm trying to use grep on words to find a word that contains each of the vowels in the correct order. To find how many such words are there. It's in /root/words I'll try that grep '.*a.*e.*i.*o.*u' /usr/share/dict/words
– Anonymous
8 hours ago











1 Answer
1






active

oldest

votes

















up vote
0
down vote



accepted










From man:




-c, --count




Suppress normal output; instead, print a count of matching lines for each input file.






share|improve this answer




















  • Thank you and everyone else.
    – Anonymous
    8 hours ago

















1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
0
down vote



accepted










From man:




-c, --count




Suppress normal output; instead, print a count of matching lines for each input file.






share|improve this answer




















  • Thank you and everyone else.
    – Anonymous
    8 hours ago














up vote
0
down vote



accepted










From man:




-c, --count




Suppress normal output; instead, print a count of matching lines for each input file.






share|improve this answer




















  • Thank you and everyone else.
    – Anonymous
    8 hours ago












up vote
0
down vote



accepted







up vote
0
down vote



accepted






From man:




-c, --count




Suppress normal output; instead, print a count of matching lines for each input file.






share|improve this answer












From man:




-c, --count




Suppress normal output; instead, print a count of matching lines for each input file.







share|improve this answer












share|improve this answer



share|improve this answer










answered 8 hours ago









msp9011

3,65043862




3,65043862











  • Thank you and everyone else.
    – Anonymous
    8 hours ago
















  • Thank you and everyone else.
    – Anonymous
    8 hours ago















Thank you and everyone else.
– Anonymous
8 hours ago




Thank you and everyone else.
– Anonymous
8 hours ago


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