Assign variable using multiple lines
Clash Royale CLAN TAG#URR8PPP
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0
down vote
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I have a function
f()
echo 777
and a variable to which I assign the "return value" of the function.
x=$(f)
Very concise! However, in my real code, the variable and function names are quite a bit longer and the function also eats positional arguments, so that concise line above, gets very long. Since I like to keep things tidy, I would like to break the code above in two lines.
x=
$(f)
Still works! But: keeping things tidy also means respecting the indentation, so that gives something like
if foo
x=
$(f)
fi
which does not work anymore due to whitespaces! Is there a good workaround for this?
bash newlines assignment
asked 8 mins ago
pfnuesel
2,62741838
add a comment |Â
up vote
0
down vote
favorite
I have a function
f()
echo 777
and a variable to which I assign the "return value" of the function.
x=$(f)
Very concise! However, in my real code, the variable and function names are quite a bit longer and the function also eats positional arguments, so that concise line above, gets very long. Since I like to keep things tidy, I would like to break the code above in two lines.
x=
$(f)
Still works! But: keeping things tidy also means respecting the indentation, so that gives something like
if foo
x=
$(f)
fi
which does not work anymore due to whitespaces! Is there a good workaround for this?
bash newlines assignment
asked 8 mins ago
pfnuesel
2,62741838
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have a function
f()
echo 777
and a variable to which I assign the "return value" of the function.
x=$(f)
Very concise! However, in my real code, the variable and function names are quite a bit longer and the function also eats positional arguments, so that concise line above, gets very long. Since I like to keep things tidy, I would like to break the code above in two lines.
x=
$(f)
Still works! But: keeping things tidy also means respecting the indentation, so that gives something like
if foo
x=
$(f)
fi
which does not work anymore due to whitespaces! Is there a good workaround for this?
bash newlines assignment
asked 8 mins ago
pfnuesel
2,62741838
I have a function
f()
echo 777
and a variable to which I assign the "return value" of the function.
x=$(f)
Very concise! However, in my real code, the variable and function names are quite a bit longer and the function also eats positional arguments, so that concise line above, gets very long. Since I like to keep things tidy, I would like to break the code above in two lines.
x=
$(f)
Still works! But: keeping things tidy also means respecting the indentation, so that gives something like
if foo
x=
$(f)
fi
which does not work anymore due to whitespaces! Is there a good workaround for this?
bash newlines assignment
bash newlines assignment
asked 8 mins ago
pfnuesel
2,62741838
asked 8 mins ago
pfnuesel
2,62741838
asked 8 mins ago
pfnuesel
2,62741838
asked 8 mins ago
pfnuesel
2,62741838
asked 8 mins ago
pfnuesel
2,62741838
2,62741838
add a comment |Â
add a comment |Â
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