I want to extract part of a line using sed and backreference

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP











up vote
-1
down vote

favorite












 1.The Greater Company :(Ranked 2) 
 5.United Taxi Service :(Ranked 3) 
31.The Cacao Company :(Ranked 4) 
40.Monster Inc. :(Ranked 5)
55.Afala, Industrial Strength :(Ranked 6) 
60.The North Company :(Ranked 7)


I want to display just the company number and company name. I do not want the rest of the line to be displayed.



 1.The Greater Company 
 5.United Taxi Service 
31.The Cacao Company 
40.Monster Inc. 
55.Afala, Industrial Strength 
60.The North Company


I can do this by sed 's/: .* //' filename.txt. How would I use this pattern with back reference so I can achieve the above result. The pattern that I want to match would be ([0-9]* .* :).




ubuntu sed reference




share|improve this question


















  • 1




    It appears that you're removing the ranking, not "extracting the company number and rank"; can you clarify your goal vs your output?
    – Jeff Schaller
    Feb 16 at 1:13










  • I edited it. What i meant was just have the result being displayed like that. I can do this with sed by using sed 's/: .*//' filename.txt, but i want to know how to achieve this by using backreference.
    – Rashad
    Feb 16 at 1:17










  • When somebody asks “How do I do X?”, we always ask “What have you tried?”  Have you read any documentation?  What part of it did you not understand?  And is that a :) smiley face at the end of your question?  Or are you saying that the pattern that you want to match is [0-9]* .* :, but you’re putting it in parentheses instead of quotes — this, when the input text contains parentheses (but not quotes).  That is very confusing. … (Cont’d)
    – G-Man
    Feb 16 at 4:37










  • (Cont’d) …  What’s more confusing: you say that you want to match [0-9]*  …, but your data don’t have a space after the number. And you say that you want to match … :, but your sample output shows that you don’t want to match the colon (:), just everything up to it.
    – G-Man
    Feb 16 at 4:37














up vote
-1
down vote

favorite












 1.The Greater Company :(Ranked 2) 
 5.United Taxi Service :(Ranked 3) 
31.The Cacao Company :(Ranked 4) 
40.Monster Inc. :(Ranked 5)
55.Afala, Industrial Strength :(Ranked 6) 
60.The North Company :(Ranked 7)


I want to display just the company number and company name. I do not want the rest of the line to be displayed.



 1.The Greater Company 
 5.United Taxi Service 
31.The Cacao Company 
40.Monster Inc. 
55.Afala, Industrial Strength 
60.The North Company


I can do this by sed 's/: .* //' filename.txt. How would I use this pattern with back reference so I can achieve the above result. The pattern that I want to match would be ([0-9]* .* :).




ubuntu sed reference




share|improve this question


















  • 1




    It appears that you're removing the ranking, not "extracting the company number and rank"; can you clarify your goal vs your output?
    – Jeff Schaller
    Feb 16 at 1:13










  • I edited it. What i meant was just have the result being displayed like that. I can do this with sed by using sed 's/: .*//' filename.txt, but i want to know how to achieve this by using backreference.
    – Rashad
    Feb 16 at 1:17










  • When somebody asks “How do I do X?”, we always ask “What have you tried?”  Have you read any documentation?  What part of it did you not understand?  And is that a :) smiley face at the end of your question?  Or are you saying that the pattern that you want to match is [0-9]* .* :, but you’re putting it in parentheses instead of quotes — this, when the input text contains parentheses (but not quotes).  That is very confusing. … (Cont’d)
    – G-Man
    Feb 16 at 4:37










  • (Cont’d) …  What’s more confusing: you say that you want to match [0-9]*  …, but your data don’t have a space after the number. And you say that you want to match … :, but your sample output shows that you don’t want to match the colon (:), just everything up to it.
    – G-Man
    Feb 16 at 4:37












up vote
-1
down vote

favorite









up vote
-1
down vote

favorite











 1.The Greater Company :(Ranked 2) 
 5.United Taxi Service :(Ranked 3) 
31.The Cacao Company :(Ranked 4) 
40.Monster Inc. :(Ranked 5)
55.Afala, Industrial Strength :(Ranked 6) 
60.The North Company :(Ranked 7)


I want to display just the company number and company name. I do not want the rest of the line to be displayed.



 1.The Greater Company 
 5.United Taxi Service 
31.The Cacao Company 
40.Monster Inc. 
55.Afala, Industrial Strength 
60.The North Company


I can do this by sed 's/: .* //' filename.txt. How would I use this pattern with back reference so I can achieve the above result. The pattern that I want to match would be ([0-9]* .* :).




ubuntu sed reference




share|improve this question














 1.The Greater Company :(Ranked 2) 
 5.United Taxi Service :(Ranked 3) 
31.The Cacao Company :(Ranked 4) 
40.Monster Inc. :(Ranked 5)
55.Afala, Industrial Strength :(Ranked 6) 
60.The North Company :(Ranked 7)


I want to display just the company number and company name. I do not want the rest of the line to be displayed.



 1.The Greater Company 
 5.United Taxi Service 
31.The Cacao Company 
40.Monster Inc. 
55.Afala, Industrial Strength 
60.The North Company


I can do this by sed 's/: .* //' filename.txt. How would I use this pattern with back reference so I can achieve the above result. The pattern that I want to match would be ([0-9]* .* :).





ubuntu sed reference





share|improve this question













share|improve this question




share|improve this question








edited Feb 28 at 22:33









Drakonoved

674518




674518










asked Feb 16 at 1:08









Rashad

568




568







  • 1




    It appears that you're removing the ranking, not "extracting the company number and rank"; can you clarify your goal vs your output?
    – Jeff Schaller
    Feb 16 at 1:13










  • I edited it. What i meant was just have the result being displayed like that. I can do this with sed by using sed 's/: .*//' filename.txt, but i want to know how to achieve this by using backreference.
    – Rashad
    Feb 16 at 1:17










  • When somebody asks “How do I do X?”, we always ask “What have you tried?”  Have you read any documentation?  What part of it did you not understand?  And is that a :) smiley face at the end of your question?  Or are you saying that the pattern that you want to match is [0-9]* .* :, but you’re putting it in parentheses instead of quotes — this, when the input text contains parentheses (but not quotes).  That is very confusing. … (Cont’d)
    – G-Man
    Feb 16 at 4:37










  • (Cont’d) …  What’s more confusing: you say that you want to match [0-9]*  …, but your data don’t have a space after the number. And you say that you want to match … :, but your sample output shows that you don’t want to match the colon (:), just everything up to it.
    – G-Man
    Feb 16 at 4:37












  • 1




    It appears that you're removing the ranking, not "extracting the company number and rank"; can you clarify your goal vs your output?
    – Jeff Schaller
    Feb 16 at 1:13










  • I edited it. What i meant was just have the result being displayed like that. I can do this with sed by using sed 's/: .*//' filename.txt, but i want to know how to achieve this by using backreference.
    – Rashad
    Feb 16 at 1:17










  • When somebody asks “How do I do X?”, we always ask “What have you tried?”  Have you read any documentation?  What part of it did you not understand?  And is that a :) smiley face at the end of your question?  Or are you saying that the pattern that you want to match is [0-9]* .* :, but you’re putting it in parentheses instead of quotes — this, when the input text contains parentheses (but not quotes).  That is very confusing. … (Cont’d)
    – G-Man
    Feb 16 at 4:37










  • (Cont’d) …  What’s more confusing: you say that you want to match [0-9]*  …, but your data don’t have a space after the number. And you say that you want to match … :, but your sample output shows that you don’t want to match the colon (:), just everything up to it.
    – G-Man
    Feb 16 at 4:37







1




1




It appears that you're removing the ranking, not "extracting the company number and rank"; can you clarify your goal vs your output?
– Jeff Schaller
Feb 16 at 1:13




It appears that you're removing the ranking, not "extracting the company number and rank"; can you clarify your goal vs your output?
– Jeff Schaller
Feb 16 at 1:13












I edited it. What i meant was just have the result being displayed like that. I can do this with sed by using sed 's/: .*//' filename.txt, but i want to know how to achieve this by using backreference.
– Rashad
Feb 16 at 1:17




I edited it. What i meant was just have the result being displayed like that. I can do this with sed by using sed 's/: .*//' filename.txt, but i want to know how to achieve this by using backreference.
– Rashad
Feb 16 at 1:17












When somebody asks “How do I do X?”, we always ask “What have you tried?”  Have you read any documentation?  What part of it did you not understand?  And is that a :) smiley face at the end of your question?  Or are you saying that the pattern that you want to match is [0-9]* .* :, but you’re putting it in parentheses instead of quotes — this, when the input text contains parentheses (but not quotes).  That is very confusing. … (Cont’d)
– G-Man
Feb 16 at 4:37




When somebody asks “How do I do X?”, we always ask “What have you tried?”  Have you read any documentation?  What part of it did you not understand?  And is that a :) smiley face at the end of your question?  Or are you saying that the pattern that you want to match is [0-9]* .* :, but you’re putting it in parentheses instead of quotes — this, when the input text contains parentheses (but not quotes).  That is very confusing. … (Cont’d)
– G-Man
Feb 16 at 4:37












(Cont’d) …  What’s more confusing: you say that you want to match [0-9]*  …, but your data don’t have a space after the number. And you say that you want to match … :, but your sample output shows that you don’t want to match the colon (:), just everything up to it.
– G-Man
Feb 16 at 4:37




(Cont’d) …  What’s more confusing: you say that you want to match [0-9]*  …, but your data don’t have a space after the number. And you say that you want to match … :, but your sample output shows that you don’t want to match the colon (:), just everything up to it.
– G-Man
Feb 16 at 4:37










2 Answers
2






active

oldest

votes

















up vote
1
down vote



accepted










If all of the lines begin with [0-9]* there's no need to match it explicitly: just capture up to (but not including) the : delimiter



sed 's/(^[^:]*) :.*/1/' file
 1.The Greater Company
 5.United Taxi Service
 31.The Cacao Company
 40.Monster Inc.
 55.Afala, Industrial Strength
 60.The North Company





share|improve this answer




















  • could you explain the command and how the back referencing works
    – Rashad
    Feb 16 at 1:28










  • @Rashad the pattern between ( and ) is captured, and then it is backreferenced as 1. See for example Regular Expression Reference: Capturing Groups and Backreferences
    – steeldriver
    Feb 16 at 1:34










  • You can omit the second colon: sed 's/(^[^:]*) .*/1/'
    – dessert
    Feb 16 at 7:44


















up vote
-2
down vote













grep -Pioe 's*d+.s*(w+[.,]? )+:' file





share|improve this answer






















  • The question asks how to do this with back reference.   Does your answer use back reference?  Can you explain how?
    – G-Man
    Feb 16 at 4:22










Your Answer







StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "106"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
convertImagesToLinks: false,
noModals: false,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);








 

draft saved


draft discarded


















StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f424507%2fi-want-to-extract-part-of-a-line-using-sed-and-backreference%23new-answer', 'question_page');

);

Post as a guest

















2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
1
down vote



accepted










If all of the lines begin with [0-9]* there's no need to match it explicitly: just capture up to (but not including) the : delimiter



sed 's/(^[^:]*) :.*/1/' file
 1.The Greater Company
 5.United Taxi Service
 31.The Cacao Company
 40.Monster Inc.
 55.Afala, Industrial Strength
 60.The North Company





share|improve this answer




















  • could you explain the command and how the back referencing works
    – Rashad
    Feb 16 at 1:28










  • @Rashad the pattern between ( and ) is captured, and then it is backreferenced as 1. See for example Regular Expression Reference: Capturing Groups and Backreferences
    – steeldriver
    Feb 16 at 1:34










  • You can omit the second colon: sed 's/(^[^:]*) .*/1/'
    – dessert
    Feb 16 at 7:44















up vote
1
down vote



accepted










If all of the lines begin with [0-9]* there's no need to match it explicitly: just capture up to (but not including) the : delimiter



sed 's/(^[^:]*) :.*/1/' file
 1.The Greater Company
 5.United Taxi Service
 31.The Cacao Company
 40.Monster Inc.
 55.Afala, Industrial Strength
 60.The North Company





share|improve this answer




















  • could you explain the command and how the back referencing works
    – Rashad
    Feb 16 at 1:28










  • @Rashad the pattern between ( and ) is captured, and then it is backreferenced as 1. See for example Regular Expression Reference: Capturing Groups and Backreferences
    – steeldriver
    Feb 16 at 1:34










  • You can omit the second colon: sed 's/(^[^:]*) .*/1/'
    – dessert
    Feb 16 at 7:44













up vote
1
down vote



accepted







up vote
1
down vote



accepted






If all of the lines begin with [0-9]* there's no need to match it explicitly: just capture up to (but not including) the : delimiter



sed 's/(^[^:]*) :.*/1/' file
 1.The Greater Company
 5.United Taxi Service
 31.The Cacao Company
 40.Monster Inc.
 55.Afala, Industrial Strength
 60.The North Company





share|improve this answer












If all of the lines begin with [0-9]* there's no need to match it explicitly: just capture up to (but not including) the : delimiter



sed 's/(^[^:]*) :.*/1/' file
 1.The Greater Company
 5.United Taxi Service
 31.The Cacao Company
 40.Monster Inc.
 55.Afala, Industrial Strength
 60.The North Company






share|improve this answer












share|improve this answer



share|improve this answer










answered Feb 16 at 1:19









steeldriver

31.5k34978




31.5k34978











  • could you explain the command and how the back referencing works
    – Rashad
    Feb 16 at 1:28










  • @Rashad the pattern between ( and ) is captured, and then it is backreferenced as 1. See for example Regular Expression Reference: Capturing Groups and Backreferences
    – steeldriver
    Feb 16 at 1:34










  • You can omit the second colon: sed 's/(^[^:]*) .*/1/'
    – dessert
    Feb 16 at 7:44

















  • could you explain the command and how the back referencing works
    – Rashad
    Feb 16 at 1:28










  • @Rashad the pattern between ( and ) is captured, and then it is backreferenced as 1. See for example Regular Expression Reference: Capturing Groups and Backreferences
    – steeldriver
    Feb 16 at 1:34










  • You can omit the second colon: sed 's/(^[^:]*) .*/1/'
    – dessert
    Feb 16 at 7:44
















could you explain the command and how the back referencing works
– Rashad
Feb 16 at 1:28




could you explain the command and how the back referencing works
– Rashad
Feb 16 at 1:28












@Rashad the pattern between ( and ) is captured, and then it is backreferenced as 1. See for example Regular Expression Reference: Capturing Groups and Backreferences
– steeldriver
Feb 16 at 1:34




@Rashad the pattern between ( and ) is captured, and then it is backreferenced as 1. See for example Regular Expression Reference: Capturing Groups and Backreferences
– steeldriver
Feb 16 at 1:34












You can omit the second colon: sed 's/(^[^:]*) .*/1/'
– dessert
Feb 16 at 7:44





You can omit the second colon: sed 's/(^[^:]*) .*/1/'
– dessert
Feb 16 at 7:44













up vote
-2
down vote













grep -Pioe 's*d+.s*(w+[.,]? )+:' file





share|improve this answer






















  • The question asks how to do this with back reference.   Does your answer use back reference?  Can you explain how?
    – G-Man
    Feb 16 at 4:22














up vote
-2
down vote













grep -Pioe 's*d+.s*(w+[.,]? )+:' file





share|improve this answer






















  • The question asks how to do this with back reference.   Does your answer use back reference?  Can you explain how?
    – G-Man
    Feb 16 at 4:22












up vote
-2
down vote










up vote
-2
down vote









grep -Pioe 's*d+.s*(w+[.,]? )+:' file





share|improve this answer














grep -Pioe 's*d+.s*(w+[.,]? )+:' file






share|improve this answer














share|improve this answer



share|improve this answer








edited Feb 16 at 2:36

























answered Feb 16 at 2:22









Budi

112




112











  • The question asks how to do this with back reference.   Does your answer use back reference?  Can you explain how?
    – G-Man
    Feb 16 at 4:22
















  • The question asks how to do this with back reference.   Does your answer use back reference?  Can you explain how?
    – G-Man
    Feb 16 at 4:22















The question asks how to do this with back reference.   Does your answer use back reference?  Can you explain how?
– G-Man
Feb 16 at 4:22




The question asks how to do this with back reference.   Does your answer use back reference?  Can you explain how?
– G-Man
Feb 16 at 4:22












 

draft saved


draft discarded


























 


draft saved


draft discarded














StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2funix.stackexchange.com%2fquestions%2f424507%2fi-want-to-extract-part-of-a-line-using-sed-and-backreference%23new-answer', 'question_page');

);

Post as a guest
































































-

Popular posts from this blog

How to check contact read email or not when send email to Individual?

Image
Clash Royale CLAN TAG #URR8PPP up vote 1 down vote favorite I'm using WordPress 4.9.8, CiviCRM to 5.5.1, I usually send email to contact by Search> Find contacts View contact details Action> Send email Send email ok, Contact received mail ok like picture But status only Email sent though contact read email or not. So, can CiviCRM can change status to Email read when contact read email? wordpress email share | improve this question asked Sep 26 at 0:12 ToanLuong 49 9 add a comment  |  up vote 1 down vote favorite I'm using WordPress 4.9.8, CiviCRM to 5.5.1, I usually send email to contact by Search> Find contacts View contact details Action> Send email Send email ok, Contact received mail ok like picture But status only Email sent though contact read email or not. So, can CiviCRM can change status to Email read when contact read email? wordpress email share | improve this question asked Se
Read more

Bahrain

Image
For other uses, see Bahrain (disambiguation). Sovereign island state in the Persian Gulf Kingdom of Bahrain مملكة البحرين   (Arabic) Mamlakat al-Baḥrayn Flag Coat of arms Anthem:  نشيد البحرين الوطني Bahrainona Our Bahrain Location of   Bahrain    (circled in red) Capital and largest city Manama 26°13′N 50°35′E  /  26.217°N 50.583°E  / 26.217; 50.583 Official languages Arabic Ethnic groups (2010 [1] ) 50.7% Arab (46% Bahrani, 4.7% other Arabs) 45.5% Asian 1% European 1.2% Others Religion Islam Demonym(s) Bahraini Government Unitary constitutional monarchy • King Hamad bin Isa Al Khalifa • Crown Prince Salman bin Hamad bin Isa Al Khalifa • Prime Minister Khalifa bin Salman Al Khalifa Legislature National Assembly • Upper house Consultative Council • Lower house Council of Representatives Independence • Declared Independence [2] 14 August 1971 • from United Kingdom [1] 15 August 1971 • Admitted to the United Nations 21 September 1971 • Kingdom of Bahrain 14 February 2002
Read more

Postfix configuration issue with fips on centos 7; mailgun relay

Image
Clash Royale CLAN TAG #URR8PPP up vote 0 down vote favorite I am trying to setup postfix to relay all mail generated on the local machine via SMTP to a mailgun relay. I have used the mailgun relay before with success on an ubuntu server, but I am migrating to a Centos 7 server which I will be running in FIPS mode. There error log is below, slightly sanitized. I have a small enough network that I choose to have each machine reach out to mailgun individually (this the loopback-only, 127.0.0.0/8 restrictions) and no firewall open port allowing smtp in to the machine. I assume the FIPS mode (and with it disabling of MD5) is causing problems, but I don't know how to overcome it or if it is even possible for tls_fprint to use some supported hash such as sha256 or sha512. However, the relay=none is slightly concerning since I have relayhost set, but perhaps that is because the smtp process is failing? Any help would be appreciated! postconf -n: alias_database = hash:/etc/alia
Read more