Why only one side of NR work? [duplicate]

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  • How to insert bash variables in awk?

    3 answers



  • Using bash variable with escape character in awk to extract lines from file

    1 answer



I am very confused about one simple script with awk: I want to print a range of rows by passing variables, the script below works:



awk ' if (NR >10 && NR < 100 ) print $0 ' file


the script below works too:



set fac = 10
awk ' if (NR >$fac && NR < 100 ) print $0 ' file


BUT this script NOT works, WHY? I am so confused. thank you for help.



set fac = 100
awk ' if (NR >10 && NR <$fac ) print $0 ' file



awk less




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marked as duplicate by Thomas Dickey, jasonwryan, αғsнιη, muru, Kiwy Jun 14 at 10:27


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.














  • There are many duplicates for this...
    – Thomas Dickey
    Jun 14 at 1:13






  • 1




    also I don't think so your second commmad does works, it will be NR >0 && NR < 100 and you will getting first 99 lines and third command NR >10 && NR <0 and since no NR is <0 then it won't print anything at all
    – Î±Ò“sнιη
    Jun 14 at 1:52











  • @ThomasDickey, thank you. With your hint, I figure out how to get it work by adding "-v" like below, but still not sure why the second script work? awk -v a="$fac1" -v b="$fac2" 'if (NR>a && NR<b) print $0'
    – kelly
    Jun 14 at 2:07















up vote
0
down vote

favorite













This question already has an answer here:



  • How to insert bash variables in awk?

    3 answers



  • Using bash variable with escape character in awk to extract lines from file

    1 answer



I am very confused about one simple script with awk: I want to print a range of rows by passing variables, the script below works:



awk ' if (NR >10 && NR < 100 ) print $0 ' file


the script below works too:



set fac = 10
awk ' if (NR >$fac && NR < 100 ) print $0 ' file


BUT this script NOT works, WHY? I am so confused. thank you for help.



set fac = 100
awk ' if (NR >10 && NR <$fac ) print $0 ' file



awk less




share|improve this question











marked as duplicate by Thomas Dickey, jasonwryan, αғsнιη, muru, Kiwy Jun 14 at 10:27


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.














  • There are many duplicates for this...
    – Thomas Dickey
    Jun 14 at 1:13






  • 1




    also I don't think so your second commmad does works, it will be NR >0 && NR < 100 and you will getting first 99 lines and third command NR >10 && NR <0 and since no NR is <0 then it won't print anything at all
    – Î±Ò“sнιη
    Jun 14 at 1:52











  • @ThomasDickey, thank you. With your hint, I figure out how to get it work by adding "-v" like below, but still not sure why the second script work? awk -v a="$fac1" -v b="$fac2" 'if (NR>a && NR<b) print $0'
    – kelly
    Jun 14 at 2:07













up vote
0
down vote

favorite









up vote
0
down vote

favorite












This question already has an answer here:



  • How to insert bash variables in awk?

    3 answers



  • Using bash variable with escape character in awk to extract lines from file

    1 answer



I am very confused about one simple script with awk: I want to print a range of rows by passing variables, the script below works:



awk ' if (NR >10 && NR < 100 ) print $0 ' file


the script below works too:



set fac = 10
awk ' if (NR >$fac && NR < 100 ) print $0 ' file


BUT this script NOT works, WHY? I am so confused. thank you for help.



set fac = 100
awk ' if (NR >10 && NR <$fac ) print $0 ' file



awk less




share|improve this question












This question already has an answer here:



  • How to insert bash variables in awk?

    3 answers



  • Using bash variable with escape character in awk to extract lines from file

    1 answer



I am very confused about one simple script with awk: I want to print a range of rows by passing variables, the script below works:



awk ' if (NR >10 && NR < 100 ) print $0 ' file


the script below works too:



set fac = 10
awk ' if (NR >$fac && NR < 100 ) print $0 ' file


BUT this script NOT works, WHY? I am so confused. thank you for help.



set fac = 100
awk ' if (NR >10 && NR <$fac ) print $0 ' file




This question already has an answer here:



  • How to insert bash variables in awk?

    3 answers



  • Using bash variable with escape character in awk to extract lines from file

    1 answer





awk less





share|improve this question










share|improve this question




share|improve this question









asked Jun 14 at 1:09









kelly

133




133




marked as duplicate by Thomas Dickey, jasonwryan, αғsнιη, muru, Kiwy Jun 14 at 10:27


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.






marked as duplicate by Thomas Dickey, jasonwryan, αғsнιη, muru, Kiwy Jun 14 at 10:27


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.













  • There are many duplicates for this...
    – Thomas Dickey
    Jun 14 at 1:13






  • 1




    also I don't think so your second commmad does works, it will be NR >0 && NR < 100 and you will getting first 99 lines and third command NR >10 && NR <0 and since no NR is <0 then it won't print anything at all
    – Î±Ò“sнιη
    Jun 14 at 1:52











  • @ThomasDickey, thank you. With your hint, I figure out how to get it work by adding "-v" like below, but still not sure why the second script work? awk -v a="$fac1" -v b="$fac2" 'if (NR>a && NR<b) print $0'
    – kelly
    Jun 14 at 2:07

















  • There are many duplicates for this...
    – Thomas Dickey
    Jun 14 at 1:13






  • 1




    also I don't think so your second commmad does works, it will be NR >0 && NR < 100 and you will getting first 99 lines and third command NR >10 && NR <0 and since no NR is <0 then it won't print anything at all
    – Î±Ò“sнιη
    Jun 14 at 1:52











  • @ThomasDickey, thank you. With your hint, I figure out how to get it work by adding "-v" like below, but still not sure why the second script work? awk -v a="$fac1" -v b="$fac2" 'if (NR>a && NR<b) print $0'
    – kelly
    Jun 14 at 2:07
















There are many duplicates for this...
– Thomas Dickey
Jun 14 at 1:13




There are many duplicates for this...
– Thomas Dickey
Jun 14 at 1:13




1




1




also I don't think so your second commmad does works, it will be NR >0 && NR < 100 and you will getting first 99 lines and third command NR >10 && NR <0 and since no NR is <0 then it won't print anything at all
– Î±Ò“sнιη
Jun 14 at 1:52





also I don't think so your second commmad does works, it will be NR >0 && NR < 100 and you will getting first 99 lines and third command NR >10 && NR <0 and since no NR is <0 then it won't print anything at all
– Î±Ò“sнιη
Jun 14 at 1:52













@ThomasDickey, thank you. With your hint, I figure out how to get it work by adding "-v" like below, but still not sure why the second script work? awk -v a="$fac1" -v b="$fac2" 'if (NR>a && NR<b) print $0'
– kelly
Jun 14 at 2:07





@ThomasDickey, thank you. With your hint, I figure out how to get it work by adding "-v" like below, but still not sure why the second script work? awk -v a="$fac1" -v b="$fac2" 'if (NR>a && NR<b) print $0'
– kelly
Jun 14 at 2:07
















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