Why 1 second RTO lower bound is missing in RFC 6298 Linux kernel implementation

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I was going through the implementation of RFC 6298. Then i found a statement as follows.
Whenever RTO is computed, if it is less than 1 second, then the RTO
SHOULD be rounded up to 1 second.
But this part i was not able to find in the code. There is on TCP_RTO_MIN constant which is declared as HZ/5 (200 ms). This 200 ms is the current lower bound of the RTO. Any body can explain this?
tcp
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I was going through the implementation of RFC 6298. Then i found a statement as follows.
Whenever RTO is computed, if it is less than 1 second, then the RTO
SHOULD be rounded up to 1 second.
But this part i was not able to find in the code. There is on TCP_RTO_MIN constant which is declared as HZ/5 (200 ms). This 200 ms is the current lower bound of the RTO. Any body can explain this?
tcp
add a comment |
I was going through the implementation of RFC 6298. Then i found a statement as follows.
Whenever RTO is computed, if it is less than 1 second, then the RTO
SHOULD be rounded up to 1 second.
But this part i was not able to find in the code. There is on TCP_RTO_MIN constant which is declared as HZ/5 (200 ms). This 200 ms is the current lower bound of the RTO. Any body can explain this?
tcp
I was going through the implementation of RFC 6298. Then i found a statement as follows.
Whenever RTO is computed, if it is less than 1 second, then the RTO
SHOULD be rounded up to 1 second.
But this part i was not able to find in the code. There is on TCP_RTO_MIN constant which is declared as HZ/5 (200 ms). This 200 ms is the current lower bound of the RTO. Any body can explain this?
tcp
tcp
edited Jan 29 at 3:34
Midhun P
asked Jan 29 at 3:29
Midhun PMidhun P
12
12
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