Check if any file exist in a folder when traversing through it
Clash Royale CLAN TAG#URR8PPP
0
I have this script:
local_dir="/some/dir1/"
cd $local_dir
for i in *.*
do
# do something ........
# [...........]
rm $i
done
It throws an error when the folder is empty.
*: No such file or directory
rm: cannot remove '*': No such file or directory
How can I fix that?
bash files directory
asked Jan 8 at 5:17
JokkiJokki
6
add a comment |
0
I have this script:
local_dir="/some/dir1/"
cd $local_dir
for i in *.*
do
# do something ........
# [...........]
rm $i
done
It throws an error when the folder is empty.
*: No such file or directory
rm: cannot remove '*': No such file or directory
How can I fix that?
bash files directory
asked Jan 8 at 5:17
JokkiJokki
6
add a comment |
0
0
0
I have this script:
local_dir="/some/dir1/"
cd $local_dir
for i in *.*
do
# do something ........
# [...........]
rm $i
done
It throws an error when the folder is empty.
*: No such file or directory
rm: cannot remove '*': No such file or directory
How can I fix that?
bash files directory
asked Jan 8 at 5:17
JokkiJokki
6
I have this script:
local_dir="/some/dir1/"
cd $local_dir
for i in *.*
do
# do something ........
# [...........]
rm $i
done
It throws an error when the folder is empty.
*: No such file or directory
rm: cannot remove '*': No such file or directory
How can I fix that?
bash files directory
bash files directory
asked Jan 8 at 5:17
JokkiJokki
6
asked Jan 8 at 5:17
JokkiJokki
6
asked Jan 8 at 5:17
JokkiJokki
6
asked Jan 8 at 5:17
JokkiJokki
6
asked Jan 8 at 5:17
JokkiJokki
6
6
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
0
If you want to use your original code, then you just need to check if file exists, using an if condition, i.e.:
local_dir="/some/dir1/"
cd $local_dir
for i in *.*
do
if [[ -f "$i" ]]
then
# do something ........
# [...........]
rm $i
fi
done
answered Jan 8 at 6:06
P_YadavP_Yadav
1,7563924
1
A simple -f doesn't need doubled , and don't forget that you'll miss files that don't have a . in them.
– stolenmoment
Jan 8 at 11:26
@stolenmoment, what's needed?
– Jokki
Jan 8 at 17:33
Just "if [ -f $i ]" will do, and * should get all files, not just files with a . In the name.
– stolenmoment
Jan 9 at 14:18
add a comment |
-1
try with ls
for i in $(ls)
do
# Do something
rm $i
done
answered Jan 8 at 5:38
KamarajKamaraj
2,9441513
2
Parsing the output oflsis too tricky to get right. See unix.stackexchange.com/q/128985/117549 for one example.
– Jeff Schaller
Jan 8 at 11:05
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
If you want to use your original code, then you just need to check if file exists, using an if condition, i.e.:
local_dir="/some/dir1/"
cd $local_dir
for i in *.*
do
if [[ -f "$i" ]]
then
# do something ........
# [...........]
rm $i
fi
done
answered Jan 8 at 6:06
P_YadavP_Yadav
1,7563924
1
A simple -f doesn't need doubled , and don't forget that you'll miss files that don't have a . in them.
– stolenmoment
Jan 8 at 11:26
@stolenmoment, what's needed?
– Jokki
Jan 8 at 17:33
Just "if [ -f $i ]" will do, and * should get all files, not just files with a . In the name.
– stolenmoment
Jan 9 at 14:18
add a comment |
0
If you want to use your original code, then you just need to check if file exists, using an if condition, i.e.:
local_dir="/some/dir1/"
cd $local_dir
for i in *.*
do
if [[ -f "$i" ]]
then
# do something ........
# [...........]
rm $i
fi
done
answered Jan 8 at 6:06
P_YadavP_Yadav
1,7563924
1
A simple -f doesn't need doubled , and don't forget that you'll miss files that don't have a . in them.
– stolenmoment
Jan 8 at 11:26
@stolenmoment, what's needed?
– Jokki
Jan 8 at 17:33
Just "if [ -f $i ]" will do, and * should get all files, not just files with a . In the name.
– stolenmoment
Jan 9 at 14:18
add a comment |
0
0
0
If you want to use your original code, then you just need to check if file exists, using an if condition, i.e.:
local_dir="/some/dir1/"
cd $local_dir
for i in *.*
do
if [[ -f "$i" ]]
then
# do something ........
# [...........]
rm $i
fi
done
answered Jan 8 at 6:06
P_YadavP_Yadav
1,7563924
If you want to use your original code, then you just need to check if file exists, using an if condition, i.e.:
local_dir="/some/dir1/"
cd $local_dir
for i in *.*
do
if [[ -f "$i" ]]
then
# do something ........
# [...........]
rm $i
fi
done
answered Jan 8 at 6:06
P_YadavP_Yadav
1,7563924
answered Jan 8 at 6:06
P_YadavP_Yadav
1,7563924
answered Jan 8 at 6:06
P_YadavP_Yadav
1,7563924
answered Jan 8 at 6:06
P_YadavP_Yadav
1,7563924
1,7563924
1
A simple -f doesn't need doubled , and don't forget that you'll miss files that don't have a . in them.
– stolenmoment
Jan 8 at 11:26
@stolenmoment, what's needed?
– Jokki
Jan 8 at 17:33
Just "if [ -f $i ]" will do, and * should get all files, not just files with a . In the name.
– stolenmoment
Jan 9 at 14:18
add a comment |
1
A simple -f doesn't need doubled , and don't forget that you'll miss files that don't have a . in them.
– stolenmoment
Jan 8 at 11:26
@stolenmoment, what's needed?
– Jokki
Jan 8 at 17:33
Just "if [ -f $i ]" will do, and * should get all files, not just files with a . In the name.
– stolenmoment
Jan 9 at 14:18
1
1
A simple -f doesn't need doubled , and don't forget that you'll miss files that don't have a . in them.
– stolenmoment
Jan 8 at 11:26
A simple -f doesn't need doubled , and don't forget that you'll miss files that don't have a . in them.
– stolenmoment
Jan 8 at 11:26
@stolenmoment, what's needed?
– Jokki
Jan 8 at 17:33
@stolenmoment, what's needed?
– Jokki
Jan 8 at 17:33
Just "if [ -f $i ]" will do, and * should get all files, not just files with a . In the name.
– stolenmoment
Jan 9 at 14:18
Just "if [ -f $i ]" will do, and * should get all files, not just files with a . In the name.
– stolenmoment
Jan 9 at 14:18
add a comment |
-1
try with ls
for i in $(ls)
do
# Do something
rm $i
done
answered Jan 8 at 5:38
KamarajKamaraj
2,9441513
2
Parsing the output oflsis too tricky to get right. See unix.stackexchange.com/q/128985/117549 for one example.
– Jeff Schaller
Jan 8 at 11:05
add a comment |
-1
try with ls
for i in $(ls)
do
# Do something
rm $i
done
answered Jan 8 at 5:38
KamarajKamaraj
2,9441513
2
Parsing the output oflsis too tricky to get right. See unix.stackexchange.com/q/128985/117549 for one example.
– Jeff Schaller
Jan 8 at 11:05
add a comment |
-1
-1
-1
try with ls
for i in $(ls)
do
# Do something
rm $i
done
answered Jan 8 at 5:38
KamarajKamaraj
2,9441513
try with ls
for i in $(ls)
do
# Do something
rm $i
done
answered Jan 8 at 5:38
KamarajKamaraj
2,9441513
answered Jan 8 at 5:38
KamarajKamaraj
2,9441513
answered Jan 8 at 5:38
KamarajKamaraj
2,9441513
answered Jan 8 at 5:38
KamarajKamaraj
2,9441513
2,9441513
2
Parsing the output oflsis too tricky to get right. See unix.stackexchange.com/q/128985/117549 for one example.
– Jeff Schaller
Jan 8 at 11:05
add a comment |
2
Parsing the output oflsis too tricky to get right. See unix.stackexchange.com/q/128985/117549 for one example.
– Jeff Schaller
Jan 8 at 11:05
2
2
Parsing the output of
ls is too tricky to get right. See unix.stackexchange.com/q/128985/117549 for one example.– Jeff Schaller
Jan 8 at 11:05
Parsing the output of
ls is too tricky to get right. See unix.stackexchange.com/q/128985/117549 for one example.– Jeff Schaller
Jan 8 at 11:05
add a comment |
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