Print only specific part of lines from a command output
Clash Royale CLAN TAG#URR8PPP
My command output is like this
Name: SLP_DCEMA100BAK01.1M__GBLON500BAK04.6M
Operation 1 Use for: 0 (backup)
Storage: stu_disk_dcema100bak01
Retention Level: 3 (1 month)
Operation 2 Use for: 1 (duplication)
Storage: stu_cc_gblon500bak04
Retention Level: 6 (6 months)
I want to print only those part that comes after ":"
Expected output is Like below
SLP_DCEMA100BAK01.1M__GBLON500BAK04.6M
0 (backup)
stu_disk_dcema100bak01
3 (1 month)
1 (duplication)
stu_cc_gblon500bak04
6 (6 months)
text-processing awk
edited Dec 19 '18 at 18:49
Jesse_b
11.9k23064
asked Dec 19 '18 at 18:46
Pradeep Aji
6
add a comment |
My command output is like this
Name: SLP_DCEMA100BAK01.1M__GBLON500BAK04.6M
Operation 1 Use for: 0 (backup)
Storage: stu_disk_dcema100bak01
Retention Level: 3 (1 month)
Operation 2 Use for: 1 (duplication)
Storage: stu_cc_gblon500bak04
Retention Level: 6 (6 months)
I want to print only those part that comes after ":"
Expected output is Like below
SLP_DCEMA100BAK01.1M__GBLON500BAK04.6M
0 (backup)
stu_disk_dcema100bak01
3 (1 month)
1 (duplication)
stu_cc_gblon500bak04
6 (6 months)
text-processing awk
edited Dec 19 '18 at 18:49
Jesse_b
11.9k23064
asked Dec 19 '18 at 18:46
Pradeep Aji
6
add a comment |
My command output is like this
Name: SLP_DCEMA100BAK01.1M__GBLON500BAK04.6M
Operation 1 Use for: 0 (backup)
Storage: stu_disk_dcema100bak01
Retention Level: 3 (1 month)
Operation 2 Use for: 1 (duplication)
Storage: stu_cc_gblon500bak04
Retention Level: 6 (6 months)
I want to print only those part that comes after ":"
Expected output is Like below
SLP_DCEMA100BAK01.1M__GBLON500BAK04.6M
0 (backup)
stu_disk_dcema100bak01
3 (1 month)
1 (duplication)
stu_cc_gblon500bak04
6 (6 months)
text-processing awk
edited Dec 19 '18 at 18:49
Jesse_b
11.9k23064
asked Dec 19 '18 at 18:46
Pradeep Aji
6
My command output is like this
Name: SLP_DCEMA100BAK01.1M__GBLON500BAK04.6M
Operation 1 Use for: 0 (backup)
Storage: stu_disk_dcema100bak01
Retention Level: 3 (1 month)
Operation 2 Use for: 1 (duplication)
Storage: stu_cc_gblon500bak04
Retention Level: 6 (6 months)
I want to print only those part that comes after ":"
Expected output is Like below
SLP_DCEMA100BAK01.1M__GBLON500BAK04.6M
0 (backup)
stu_disk_dcema100bak01
3 (1 month)
1 (duplication)
stu_cc_gblon500bak04
6 (6 months)
text-processing awk
text-processing awk
edited Dec 19 '18 at 18:49
Jesse_b
11.9k23064
asked Dec 19 '18 at 18:46
Pradeep Aji
6
edited Dec 19 '18 at 18:49
Jesse_b
11.9k23064
asked Dec 19 '18 at 18:46
Pradeep Aji
6
edited Dec 19 '18 at 18:49
Jesse_b
11.9k23064
edited Dec 19 '18 at 18:49
Jesse_b
11.9k23064
edited Dec 19 '18 at 18:49
Jesse_b
11.9k23064
11.9k23064
asked Dec 19 '18 at 18:46
Pradeep Aji
6
asked Dec 19 '18 at 18:46
Pradeep Aji
6
asked Dec 19 '18 at 18:46
Pradeep Aji
6
6
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
To remove everything up through (and including) the last : on each line,
use
sed 's/.*://'
For example,
your_command | sed 's/.*://'
If your data (the part after the label, which you want to keep)
might contain a :,
you want to remove everything up through the first : in the line:
sed 's/^[^:]://'
If you have a space after the colon (as shown in your example)
and you want to remove that, too,
just add a space after the colon in the command:
sed 's/.*: //'
or
sed 's/^[^:]: //'
answered Dec 19 '18 at 19:07
G-Man
12.9k93364
add a comment |
awk -F: 'sub(/^ /,"",$2);print $2' file
SLP_DCEMA100BAK01.1M__GBLON500BAK04.6M
0 (backup)
stu_disk_dcema100bak01
3 (1 month)
1 (duplication)
stu_cc_gblon500bak04
6 (6 months)
answered Dec 19 '18 at 23:15
Claes Wikner
13713
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
To remove everything up through (and including) the last : on each line,
use
sed 's/.*://'
For example,
your_command | sed 's/.*://'
If your data (the part after the label, which you want to keep)
might contain a :,
you want to remove everything up through the first : in the line:
sed 's/^[^:]://'
If you have a space after the colon (as shown in your example)
and you want to remove that, too,
just add a space after the colon in the command:
sed 's/.*: //'
or
sed 's/^[^:]: //'
answered Dec 19 '18 at 19:07
G-Man
12.9k93364
add a comment |
To remove everything up through (and including) the last : on each line,
use
sed 's/.*://'
For example,
your_command | sed 's/.*://'
If your data (the part after the label, which you want to keep)
might contain a :,
you want to remove everything up through the first : in the line:
sed 's/^[^:]://'
If you have a space after the colon (as shown in your example)
and you want to remove that, too,
just add a space after the colon in the command:
sed 's/.*: //'
or
sed 's/^[^:]: //'
answered Dec 19 '18 at 19:07
G-Man
12.9k93364
add a comment |
To remove everything up through (and including) the last : on each line,
use
sed 's/.*://'
For example,
your_command | sed 's/.*://'
If your data (the part after the label, which you want to keep)
might contain a :,
you want to remove everything up through the first : in the line:
sed 's/^[^:]://'
If you have a space after the colon (as shown in your example)
and you want to remove that, too,
just add a space after the colon in the command:
sed 's/.*: //'
or
sed 's/^[^:]: //'
answered Dec 19 '18 at 19:07
G-Man
12.9k93364
To remove everything up through (and including) the last : on each line,
use
sed 's/.*://'
For example,
your_command | sed 's/.*://'
If your data (the part after the label, which you want to keep)
might contain a :,
you want to remove everything up through the first : in the line:
sed 's/^[^:]://'
If you have a space after the colon (as shown in your example)
and you want to remove that, too,
just add a space after the colon in the command:
sed 's/.*: //'
or
sed 's/^[^:]: //'
answered Dec 19 '18 at 19:07
G-Man
12.9k93364
answered Dec 19 '18 at 19:07
G-Man
12.9k93364
answered Dec 19 '18 at 19:07
G-Man
12.9k93364
answered Dec 19 '18 at 19:07
G-Man
12.9k93364
12.9k93364
add a comment |
add a comment |
awk -F: 'sub(/^ /,"",$2);print $2' file
SLP_DCEMA100BAK01.1M__GBLON500BAK04.6M
0 (backup)
stu_disk_dcema100bak01
3 (1 month)
1 (duplication)
stu_cc_gblon500bak04
6 (6 months)
answered Dec 19 '18 at 23:15
Claes Wikner
13713
add a comment |
awk -F: 'sub(/^ /,"",$2);print $2' file
SLP_DCEMA100BAK01.1M__GBLON500BAK04.6M
0 (backup)
stu_disk_dcema100bak01
3 (1 month)
1 (duplication)
stu_cc_gblon500bak04
6 (6 months)
answered Dec 19 '18 at 23:15
Claes Wikner
13713
add a comment |
awk -F: 'sub(/^ /,"",$2);print $2' file
SLP_DCEMA100BAK01.1M__GBLON500BAK04.6M
0 (backup)
stu_disk_dcema100bak01
3 (1 month)
1 (duplication)
stu_cc_gblon500bak04
6 (6 months)
answered Dec 19 '18 at 23:15
Claes Wikner
13713
awk -F: 'sub(/^ /,"",$2);print $2' file
SLP_DCEMA100BAK01.1M__GBLON500BAK04.6M
0 (backup)
stu_disk_dcema100bak01
3 (1 month)
1 (duplication)
stu_cc_gblon500bak04
6 (6 months)
answered Dec 19 '18 at 23:15
Claes Wikner
13713
answered Dec 19 '18 at 23:15
Claes Wikner
13713
answered Dec 19 '18 at 23:15
Claes Wikner
13713
answered Dec 19 '18 at 23:15
Claes Wikner
13713
13713
add a comment |
add a comment |
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