Parse header in a file and based on the header replace a value in the file

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I have the following file



Field1|Field2|Field3|Field4|Field5
a|b|c|d|e
1|2|3|4|5
z|y|x|w|v


I have a script which accepts two inputs



script.sh Field3 T


The script.sh would take the 'Field3' argument and based on that column number should replace the contents with 'T'.



[edit]



I tried the following suggestion from @Costas and ran into a problem.
My file is like this:



MODULE_ColumnA~MODULE_ColumnB~MODULE_ColumnC~MODULE_ColumnD~MODULE_ColumnE
8.2~Y~N~~0


If I run the following script



cat <filename> | awk -F'~' -v p='MODULE_ColumnD' -v r='99' 'NR==1for (i=1;i<=NF;i++) if($i==p)f=i;print;next$f=r'


It replaces the value, but the delimiter is missing or replaced with space in the output as such:



MODULE_ColumnA~MODULE_ColumnB~MODULE_ColumnC~MODULE_ColumnD~MODULE_ColumnE
8.2 Y N 99 0


How do I get back the delimiter in the records?










share|improve this question























  • Why don't you pass 3 instead of Field3?
    – cuonglm
    Mar 5 '15 at 17:29










  • @cuonglm I just pasted an example to make it simpler to explain, in the actual file, the column headers are named differently and do not have the numeric suffix to them.
    – rahul
    Mar 5 '15 at 17:42






  • 1




    I mean if you pass the column number, it's easier awk -F'|' -v f=3 -v v=T 'FNR>1$f=T1' OFS='|' file
    – cuonglm
    Mar 5 '15 at 17:51










  • @cuonglm Thanks, yes it will make it easier. But the file has about 30 columns, and this script will be used as an utility for other users. So i wanted to make it simpler for them to use.
    – rahul
    Mar 5 '15 at 17:58














up vote
0
down vote

favorite
1












I have the following file



Field1|Field2|Field3|Field4|Field5
a|b|c|d|e
1|2|3|4|5
z|y|x|w|v


I have a script which accepts two inputs



script.sh Field3 T


The script.sh would take the 'Field3' argument and based on that column number should replace the contents with 'T'.



[edit]



I tried the following suggestion from @Costas and ran into a problem.
My file is like this:



MODULE_ColumnA~MODULE_ColumnB~MODULE_ColumnC~MODULE_ColumnD~MODULE_ColumnE
8.2~Y~N~~0


If I run the following script



cat <filename> | awk -F'~' -v p='MODULE_ColumnD' -v r='99' 'NR==1for (i=1;i<=NF;i++) if($i==p)f=i;print;next$f=r'


It replaces the value, but the delimiter is missing or replaced with space in the output as such:



MODULE_ColumnA~MODULE_ColumnB~MODULE_ColumnC~MODULE_ColumnD~MODULE_ColumnE
8.2 Y N 99 0


How do I get back the delimiter in the records?










share|improve this question























  • Why don't you pass 3 instead of Field3?
    – cuonglm
    Mar 5 '15 at 17:29










  • @cuonglm I just pasted an example to make it simpler to explain, in the actual file, the column headers are named differently and do not have the numeric suffix to them.
    – rahul
    Mar 5 '15 at 17:42






  • 1




    I mean if you pass the column number, it's easier awk -F'|' -v f=3 -v v=T 'FNR>1$f=T1' OFS='|' file
    – cuonglm
    Mar 5 '15 at 17:51










  • @cuonglm Thanks, yes it will make it easier. But the file has about 30 columns, and this script will be used as an utility for other users. So i wanted to make it simpler for them to use.
    – rahul
    Mar 5 '15 at 17:58












up vote
0
down vote

favorite
1









up vote
0
down vote

favorite
1






1





I have the following file



Field1|Field2|Field3|Field4|Field5
a|b|c|d|e
1|2|3|4|5
z|y|x|w|v


I have a script which accepts two inputs



script.sh Field3 T


The script.sh would take the 'Field3' argument and based on that column number should replace the contents with 'T'.



[edit]



I tried the following suggestion from @Costas and ran into a problem.
My file is like this:



MODULE_ColumnA~MODULE_ColumnB~MODULE_ColumnC~MODULE_ColumnD~MODULE_ColumnE
8.2~Y~N~~0


If I run the following script



cat <filename> | awk -F'~' -v p='MODULE_ColumnD' -v r='99' 'NR==1for (i=1;i<=NF;i++) if($i==p)f=i;print;next$f=r'


It replaces the value, but the delimiter is missing or replaced with space in the output as such:



MODULE_ColumnA~MODULE_ColumnB~MODULE_ColumnC~MODULE_ColumnD~MODULE_ColumnE
8.2 Y N 99 0


How do I get back the delimiter in the records?










share|improve this question















I have the following file



Field1|Field2|Field3|Field4|Field5
a|b|c|d|e
1|2|3|4|5
z|y|x|w|v


I have a script which accepts two inputs



script.sh Field3 T


The script.sh would take the 'Field3' argument and based on that column number should replace the contents with 'T'.



[edit]



I tried the following suggestion from @Costas and ran into a problem.
My file is like this:



MODULE_ColumnA~MODULE_ColumnB~MODULE_ColumnC~MODULE_ColumnD~MODULE_ColumnE
8.2~Y~N~~0


If I run the following script



cat <filename> | awk -F'~' -v p='MODULE_ColumnD' -v r='99' 'NR==1for (i=1;i<=NF;i++) if($i==p)f=i;print;next$f=r'


It replaces the value, but the delimiter is missing or replaced with space in the output as such:



MODULE_ColumnA~MODULE_ColumnB~MODULE_ColumnC~MODULE_ColumnD~MODULE_ColumnE
8.2 Y N 99 0


How do I get back the delimiter in the records?







bash shell-script sed awk perl






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 17 at 20:35









Rui F Ribeiro

38.2k1475123




38.2k1475123










asked Mar 5 '15 at 17:11









rahul

1,025517




1,025517











  • Why don't you pass 3 instead of Field3?
    – cuonglm
    Mar 5 '15 at 17:29










  • @cuonglm I just pasted an example to make it simpler to explain, in the actual file, the column headers are named differently and do not have the numeric suffix to them.
    – rahul
    Mar 5 '15 at 17:42






  • 1




    I mean if you pass the column number, it's easier awk -F'|' -v f=3 -v v=T 'FNR>1$f=T1' OFS='|' file
    – cuonglm
    Mar 5 '15 at 17:51










  • @cuonglm Thanks, yes it will make it easier. But the file has about 30 columns, and this script will be used as an utility for other users. So i wanted to make it simpler for them to use.
    – rahul
    Mar 5 '15 at 17:58
















  • Why don't you pass 3 instead of Field3?
    – cuonglm
    Mar 5 '15 at 17:29










  • @cuonglm I just pasted an example to make it simpler to explain, in the actual file, the column headers are named differently and do not have the numeric suffix to them.
    – rahul
    Mar 5 '15 at 17:42






  • 1




    I mean if you pass the column number, it's easier awk -F'|' -v f=3 -v v=T 'FNR>1$f=T1' OFS='|' file
    – cuonglm
    Mar 5 '15 at 17:51










  • @cuonglm Thanks, yes it will make it easier. But the file has about 30 columns, and this script will be used as an utility for other users. So i wanted to make it simpler for them to use.
    – rahul
    Mar 5 '15 at 17:58















Why don't you pass 3 instead of Field3?
– cuonglm
Mar 5 '15 at 17:29




Why don't you pass 3 instead of Field3?
– cuonglm
Mar 5 '15 at 17:29












@cuonglm I just pasted an example to make it simpler to explain, in the actual file, the column headers are named differently and do not have the numeric suffix to them.
– rahul
Mar 5 '15 at 17:42




@cuonglm I just pasted an example to make it simpler to explain, in the actual file, the column headers are named differently and do not have the numeric suffix to them.
– rahul
Mar 5 '15 at 17:42




1




1




I mean if you pass the column number, it's easier awk -F'|' -v f=3 -v v=T 'FNR>1$f=T1' OFS='|' file
– cuonglm
Mar 5 '15 at 17:51




I mean if you pass the column number, it's easier awk -F'|' -v f=3 -v v=T 'FNR>1$f=T1' OFS='|' file
– cuonglm
Mar 5 '15 at 17:51












@cuonglm Thanks, yes it will make it easier. But the file has about 30 columns, and this script will be used as an utility for other users. So i wanted to make it simpler for them to use.
– rahul
Mar 5 '15 at 17:58




@cuonglm Thanks, yes it will make it easier. But the file has about 30 columns, and this script will be used as an utility for other users. So i wanted to make it simpler for them to use.
– rahul
Mar 5 '15 at 17:58










1 Answer
1






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oldest

votes

















up vote
3
down vote



accepted










awk -F'|' -v p='Field3' -v r='T' '
NR==1
for (i=1;i<=NF;i++)
if ($i==p)
f=i
print
next
$f=r
'


If you like to format it to use like script.awk save it like:



#!/usr/bin/awk -f
BEGIN
OFS=FS="
NR==1
for (i=1;i<=NF;i++)
if ($i==p)
f=i
print
next
$f=r


and make its executable by chmod +x script.awk and use:



./script.awk p=Field4 r=T input.file





share|improve this answer






















  • You are a life saver. Thank you !!
    – rahul
    Mar 5 '15 at 17:46










  • I ran into another problem while trying your suggestion. Unfortunately I'm not able to add the explanation as a comment, so I`ve edited my question to include details.
    – rahul
    Mar 9 '15 at 13:26







  • 1




    @rahul If you use variant with -F'~' option add -v OFS='~' (Output Field Separator)
    – Costas
    Mar 9 '15 at 15:30











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1 Answer
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up vote
3
down vote



accepted










awk -F'|' -v p='Field3' -v r='T' '
NR==1
for (i=1;i<=NF;i++)
if ($i==p)
f=i
print
next
$f=r
'


If you like to format it to use like script.awk save it like:



#!/usr/bin/awk -f
BEGIN
OFS=FS="
NR==1
for (i=1;i<=NF;i++)
if ($i==p)
f=i
print
next
$f=r


and make its executable by chmod +x script.awk and use:



./script.awk p=Field4 r=T input.file





share|improve this answer






















  • You are a life saver. Thank you !!
    – rahul
    Mar 5 '15 at 17:46










  • I ran into another problem while trying your suggestion. Unfortunately I'm not able to add the explanation as a comment, so I`ve edited my question to include details.
    – rahul
    Mar 9 '15 at 13:26







  • 1




    @rahul If you use variant with -F'~' option add -v OFS='~' (Output Field Separator)
    – Costas
    Mar 9 '15 at 15:30















up vote
3
down vote



accepted










awk -F'|' -v p='Field3' -v r='T' '
NR==1
for (i=1;i<=NF;i++)
if ($i==p)
f=i
print
next
$f=r
'


If you like to format it to use like script.awk save it like:



#!/usr/bin/awk -f
BEGIN
OFS=FS="
NR==1
for (i=1;i<=NF;i++)
if ($i==p)
f=i
print
next
$f=r


and make its executable by chmod +x script.awk and use:



./script.awk p=Field4 r=T input.file





share|improve this answer






















  • You are a life saver. Thank you !!
    – rahul
    Mar 5 '15 at 17:46










  • I ran into another problem while trying your suggestion. Unfortunately I'm not able to add the explanation as a comment, so I`ve edited my question to include details.
    – rahul
    Mar 9 '15 at 13:26







  • 1




    @rahul If you use variant with -F'~' option add -v OFS='~' (Output Field Separator)
    – Costas
    Mar 9 '15 at 15:30













up vote
3
down vote



accepted







up vote
3
down vote



accepted






awk -F'|' -v p='Field3' -v r='T' '
NR==1
for (i=1;i<=NF;i++)
if ($i==p)
f=i
print
next
$f=r
'


If you like to format it to use like script.awk save it like:



#!/usr/bin/awk -f
BEGIN
OFS=FS="
NR==1
for (i=1;i<=NF;i++)
if ($i==p)
f=i
print
next
$f=r


and make its executable by chmod +x script.awk and use:



./script.awk p=Field4 r=T input.file





share|improve this answer














awk -F'|' -v p='Field3' -v r='T' '
NR==1
for (i=1;i<=NF;i++)
if ($i==p)
f=i
print
next
$f=r
'


If you like to format it to use like script.awk save it like:



#!/usr/bin/awk -f
BEGIN
OFS=FS="
NR==1
for (i=1;i<=NF;i++)
if ($i==p)
f=i
print
next
$f=r


and make its executable by chmod +x script.awk and use:



./script.awk p=Field4 r=T input.file






share|improve this answer














share|improve this answer



share|improve this answer








edited Mar 5 '15 at 18:14

























answered Mar 5 '15 at 17:29









Costas

12.6k1129




12.6k1129











  • You are a life saver. Thank you !!
    – rahul
    Mar 5 '15 at 17:46










  • I ran into another problem while trying your suggestion. Unfortunately I'm not able to add the explanation as a comment, so I`ve edited my question to include details.
    – rahul
    Mar 9 '15 at 13:26







  • 1




    @rahul If you use variant with -F'~' option add -v OFS='~' (Output Field Separator)
    – Costas
    Mar 9 '15 at 15:30

















  • You are a life saver. Thank you !!
    – rahul
    Mar 5 '15 at 17:46










  • I ran into another problem while trying your suggestion. Unfortunately I'm not able to add the explanation as a comment, so I`ve edited my question to include details.
    – rahul
    Mar 9 '15 at 13:26







  • 1




    @rahul If you use variant with -F'~' option add -v OFS='~' (Output Field Separator)
    – Costas
    Mar 9 '15 at 15:30
















You are a life saver. Thank you !!
– rahul
Mar 5 '15 at 17:46




You are a life saver. Thank you !!
– rahul
Mar 5 '15 at 17:46












I ran into another problem while trying your suggestion. Unfortunately I'm not able to add the explanation as a comment, so I`ve edited my question to include details.
– rahul
Mar 9 '15 at 13:26





I ran into another problem while trying your suggestion. Unfortunately I'm not able to add the explanation as a comment, so I`ve edited my question to include details.
– rahul
Mar 9 '15 at 13:26





1




1




@rahul If you use variant with -F'~' option add -v OFS='~' (Output Field Separator)
– Costas
Mar 9 '15 at 15:30





@rahul If you use variant with -F'~' option add -v OFS='~' (Output Field Separator)
– Costas
Mar 9 '15 at 15:30


















 

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