Where is the command lines stored before it is executed?

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-1
down vote

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I have such a script in ~/draft

$ cat test.sh
#! /usr/local/bin/bash

for i in ./*;do
 echo $i
done

The chunk of code are stored in test.sh,

when I run it

$ bash test.sh
./first.html
./second.html
./test.sh
./third.html

So I run the script name test.sh and get the output.

Alternatively, I could run the command directly as:

$ for i in ./*; do echo $i; done
./first.html
./second.html
./test.sh
./third.html

The second chunk get the identical results.

Since the preceding codes resides in file test.sh, what's the filename where the command for i in ./*; do echo $i; done live?

edited 3 mins ago

Kusalananda

111k15216342

asked 1 hour ago

rider dragon

22716

New contributor

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up vote
-1
down vote

favorite

I have such a script in ~/draft

$ cat test.sh
#! /usr/local/bin/bash

for i in ./*;do
 echo $i
done

The chunk of code are stored in test.sh,

when I run it

$ bash test.sh
./first.html
./second.html
./test.sh
./third.html

So I run the script name test.sh and get the output.

Alternatively, I could run the command directly as:

$ for i in ./*; do echo $i; done
./first.html
./second.html
./test.sh
./third.html

The second chunk get the identical results.

Since the preceding codes resides in file test.sh, what's the filename where the command for i in ./*; do echo $i; done live?

edited 3 mins ago

Kusalananda

111k15216342

asked 1 hour ago

rider dragon

22716

New contributor

add a commentÂ |Â

up vote
-1
down vote

favorite

I have such a script in ~/draft

$ cat test.sh
#! /usr/local/bin/bash

for i in ./*;do
 echo $i
done

The chunk of code are stored in test.sh,

when I run it

$ bash test.sh
./first.html
./second.html
./test.sh
./third.html

So I run the script name test.sh and get the output.

Alternatively, I could run the command directly as:

$ for i in ./*; do echo $i; done
./first.html
./second.html
./test.sh
./third.html

The second chunk get the identical results.

Since the preceding codes resides in file test.sh, what's the filename where the command for i in ./*; do echo $i; done live?

edited 3 mins ago

Kusalananda

111k15216342

asked 1 hour ago

rider dragon

22716

New contributor

I have such a script in ~/draft

$ cat test.sh
#! /usr/local/bin/bash

for i in ./*;do
 echo $i
done

The chunk of code are stored in test.sh,

when I run it

$ bash test.sh
./first.html
./second.html
./test.sh
./third.html

So I run the script name test.sh and get the output.

Alternatively, I could run the command directly as:

$ for i in ./*; do echo $i; done
./first.html
./second.html
./test.sh
./third.html

The second chunk get the identical results.

Since the preceding codes resides in file test.sh, what's the filename where the command for i in ./*; do echo $i; done live?

bash

edited 3 mins ago

Kusalananda

111k15216342

asked 1 hour ago

rider dragon

22716

New contributor

edited 3 mins ago

Kusalananda

111k15216342

asked 1 hour ago

rider dragon

22716

New contributor

edited 3 mins ago

Kusalananda

111k15216342

edited 3 mins ago

Kusalananda

111k15216342

edited 3 mins ago

Kusalananda

111k15216342

asked 1 hour ago

rider dragon

22716

New contributor

asked 1 hour ago

rider dragon

22716

asked 1 hour ago

rider dragon

22716

New contributor

rider dragon is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

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Commands don't have to be stored in a file to be executed - the interpreter (in this case bash) can simply read the command line into memory like it would read a script file (with some minor caveats related to buffering) and then execute it in exactly the same way.

answered 34 mins ago

l0b0

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answered 34 mins ago

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up vote
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answered 34 mins ago

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up vote
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down vote

answered 34 mins ago

l0b0

26.8k17107236

answered 34 mins ago

l0b0

26.8k17107236

answered 34 mins ago

l0b0

26.8k17107236

answered 34 mins ago

l0b0

26.8k17107236

answered 34 mins ago

l0b0

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