echo full command to file
Clash Royale CLAN TAG#URR8PPP
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I have the following command
echo “more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST†>> NOTNY.sh && chmod 0777 NOTNY.sh
However when I run the command and view the content of NOTNY.sh it contains
“more PHONEBOOK.lst
It should contain
more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST
How do I copy the text from the command and not the result I am getting?
bash echo
asked Oct 15 '17 at 21:49
John Hamlett IV
11
add a comment |Â
up vote
0
down vote
favorite
I have the following command
echo “more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST†>> NOTNY.sh && chmod 0777 NOTNY.sh
However when I run the command and view the content of NOTNY.sh it contains
“more PHONEBOOK.lst
It should contain
more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST
How do I copy the text from the command and not the result I am getting?
bash echo
asked Oct 15 '17 at 21:49
John Hamlett IV
11
4
I'm guessing those are "smart" quotes, which your shell saw as just more bytes instead of actual quotes.
– Jeff Schaller
Oct 15 '17 at 22:03
How do I make it see the command as a whole and not evaluate the command?
– John Hamlett IV
Oct 15 '17 at 22:11
2
Quote the string. Your example contains the characters“andâ€Â(U+201C and U+201D) which are not quotes as far as the shell is concerned. The shell understands'(U+0027) and"(U+0022). The fancy curly characters featured in your example are just ordinary fancy curly characters.
– AlexP
Oct 15 '17 at 23:11
add a comment |Â
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I have the following command
echo “more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST†>> NOTNY.sh && chmod 0777 NOTNY.sh
However when I run the command and view the content of NOTNY.sh it contains
“more PHONEBOOK.lst
It should contain
more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST
How do I copy the text from the command and not the result I am getting?
bash echo
asked Oct 15 '17 at 21:49
John Hamlett IV
11
I have the following command
echo “more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST†>> NOTNY.sh && chmod 0777 NOTNY.sh
However when I run the command and view the content of NOTNY.sh it contains
“more PHONEBOOK.lst
It should contain
more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST
How do I copy the text from the command and not the result I am getting?
bash echo
asked Oct 15 '17 at 21:49
John Hamlett IV
11
asked Oct 15 '17 at 21:49
John Hamlett IV
11
asked Oct 15 '17 at 21:49
John Hamlett IV
11
asked Oct 15 '17 at 21:49
John Hamlett IV
11
11
4
I'm guessing those are "smart" quotes, which your shell saw as just more bytes instead of actual quotes.
– Jeff Schaller
Oct 15 '17 at 22:03
How do I make it see the command as a whole and not evaluate the command?
– John Hamlett IV
Oct 15 '17 at 22:11
2
Quote the string. Your example contains the characters“andâ€Â(U+201C and U+201D) which are not quotes as far as the shell is concerned. The shell understands'(U+0027) and"(U+0022). The fancy curly characters featured in your example are just ordinary fancy curly characters.
– AlexP
Oct 15 '17 at 23:11
add a comment |Â
4
I'm guessing those are "smart" quotes, which your shell saw as just more bytes instead of actual quotes.
– Jeff Schaller
Oct 15 '17 at 22:03
How do I make it see the command as a whole and not evaluate the command?
– John Hamlett IV
Oct 15 '17 at 22:11
2
Quote the string. Your example contains the characters“andâ€Â(U+201C and U+201D) which are not quotes as far as the shell is concerned. The shell understands'(U+0027) and"(U+0022). The fancy curly characters featured in your example are just ordinary fancy curly characters.
– AlexP
Oct 15 '17 at 23:11
4
4
I'm guessing those are "smart" quotes, which your shell saw as just more bytes instead of actual quotes.
– Jeff Schaller
Oct 15 '17 at 22:03
I'm guessing those are "smart" quotes, which your shell saw as just more bytes instead of actual quotes.
– Jeff Schaller
Oct 15 '17 at 22:03
How do I make it see the command as a whole and not evaluate the command?
– John Hamlett IV
Oct 15 '17 at 22:11
How do I make it see the command as a whole and not evaluate the command?
– John Hamlett IV
Oct 15 '17 at 22:11
2
2
Quote the string. Your example contains the characters
“ and †(U+201C and U+201D) which are not quotes as far as the shell is concerned. The shell understands ' (U+0027) and " (U+0022). The fancy curly characters featured in your example are just ordinary fancy curly characters.– AlexP
Oct 15 '17 at 23:11
Quote the string. Your example contains the characters
“ and †(U+201C and U+201D) which are not quotes as far as the shell is concerned. The shell understands ' (U+0027) and " (U+0022). The fancy curly characters featured in your example are just ordinary fancy curly characters.– AlexP
Oct 15 '17 at 23:11
add a comment |Â
1 Answer
1
active
oldest
votes
up vote
1
down vote
Instead of “smart†quotes, use normal "double-quotes":
printf "%sn" "more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh
Or, saving a pointless call to more, since awk will read the files you tell it to:
printf "%sn" "awk '!/ NY /' PHONEBOOK.lst | sort -k1 | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh
Or, since the second sort will just override the first one:
printf "%sn" "awk '!/ NY /' PHONEBOOK.lst | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh
answered Oct 15 '17 at 23:17
Jeff Schaller
32.1k849109
add a comment |Â
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
Instead of “smart†quotes, use normal "double-quotes":
printf "%sn" "more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh
Or, saving a pointless call to more, since awk will read the files you tell it to:
printf "%sn" "awk '!/ NY /' PHONEBOOK.lst | sort -k1 | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh
Or, since the second sort will just override the first one:
printf "%sn" "awk '!/ NY /' PHONEBOOK.lst | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh
answered Oct 15 '17 at 23:17
Jeff Schaller
32.1k849109
add a comment |Â
up vote
1
down vote
Instead of “smart†quotes, use normal "double-quotes":
printf "%sn" "more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh
Or, saving a pointless call to more, since awk will read the files you tell it to:
printf "%sn" "awk '!/ NY /' PHONEBOOK.lst | sort -k1 | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh
Or, since the second sort will just override the first one:
printf "%sn" "awk '!/ NY /' PHONEBOOK.lst | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh
answered Oct 15 '17 at 23:17
Jeff Schaller
32.1k849109
add a comment |Â
up vote
1
down vote
up vote
1
down vote
Instead of “smart†quotes, use normal "double-quotes":
printf "%sn" "more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh
Or, saving a pointless call to more, since awk will read the files you tell it to:
printf "%sn" "awk '!/ NY /' PHONEBOOK.lst | sort -k1 | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh
Or, since the second sort will just override the first one:
printf "%sn" "awk '!/ NY /' PHONEBOOK.lst | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh
answered Oct 15 '17 at 23:17
Jeff Schaller
32.1k849109
Instead of “smart†quotes, use normal "double-quotes":
printf "%sn" "more PHONEBOOK.lst | awk '!/ NY /' | sort -k1 | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh
Or, saving a pointless call to more, since awk will read the files you tell it to:
printf "%sn" "awk '!/ NY /' PHONEBOOK.lst | sort -k1 | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh
Or, since the second sort will just override the first one:
printf "%sn" "awk '!/ NY /' PHONEBOOK.lst | sort -k4 | tee PHONENOTNY.LST" >> NOTNY.sh && chmod 0777 NOTNY.sh
answered Oct 15 '17 at 23:17
Jeff Schaller
32.1k849109
edited Oct 16 '17 at 21:49
answered Oct 15 '17 at 23:17
Jeff Schaller
32.1k849109
answered Oct 15 '17 at 23:17
Jeff Schaller
32.1k849109
answered Oct 15 '17 at 23:17
Jeff Schaller
32.1k849109
32.1k849109
add a comment |Â
add a comment |Â
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4
I'm guessing those are "smart" quotes, which your shell saw as just more bytes instead of actual quotes.
– Jeff Schaller
Oct 15 '17 at 22:03
How do I make it see the command as a whole and not evaluate the command?
– John Hamlett IV
Oct 15 '17 at 22:11
2
Quote the string. Your example contains the characters
“andâ€Â(U+201C and U+201D) which are not quotes as far as the shell is concerned. The shell understands'(U+0027) and"(U+0022). The fancy curly characters featured in your example are just ordinary fancy curly characters.– AlexP
Oct 15 '17 at 23:11