capture ip packets when the gateway is not the ISP router

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In my home network I have the following topology



 Internet
|
wifi |
C ----------- A ---------- B


where



  • A (static IP 192.168.0.254) is the router/AP given by my ISP.

  • B (static IP 192.168.0.1) is a linux machine working as local DNS and DHCP server (running dnsmasq)

  • C is any client connecting to the AP and configured by DHCP.

For now, the default gateway supplied by B (as DHCP server) is just A.



Then, suppose I want to capture in B all traffic coming from any client C. Here's what I did on B:




  1. activate IP forwarding with



    # sysctl net.ipv4.ip_forward=1"


  2. supply B as gateway. Of course, B itself uses A as its own gateway


  3. run tcpdump on B to see what's going on

On a client C, I start any request, e.g.



$ traceroute www.google.com


Now, I expect that traffic originating from C is routed to B, then to A and finally to the internet.



What works. C is able to reach the internet



What does not work. Except for the first request, it seems that B is completely bypassed: tcpdump does not show anything; the address of B doesn't show up in the traceroute output. Still, I'm sure that reroute takes place because C is cut out from internet if I disable IP forwarding on B.



If some sort of short-curcuit is happening, how can I avoid it?



Disclaimer: I know that changing the network topology could solve the "capture all traffic" problem (e.g. by port mirroring etc.), but I really want to understand what's going on with my setup and how to fix that without changing topology.







share|improve this question
















  • 1




    Assuming you wanted to say "C uses B as gateway, while B uses A as gateway", then this will only work if A bridges WLAN and LAN, because otherwise C and B are not in the same segment. So you need to get into the A via ssh or otherwise, and look and possible change what A does. If A just forwards packets from C to the internet, there's nothing you can do unless you can change the way A works (e.g. by flashing it with OpenWRT).
    – dirkt
    Nov 20 '17 at 11:18














up vote
0
down vote

favorite












In my home network I have the following topology



 Internet
|
wifi |
C ----------- A ---------- B


where



  • A (static IP 192.168.0.254) is the router/AP given by my ISP.

  • B (static IP 192.168.0.1) is a linux machine working as local DNS and DHCP server (running dnsmasq)

  • C is any client connecting to the AP and configured by DHCP.

For now, the default gateway supplied by B (as DHCP server) is just A.



Then, suppose I want to capture in B all traffic coming from any client C. Here's what I did on B:




  1. activate IP forwarding with



    # sysctl net.ipv4.ip_forward=1"


  2. supply B as gateway. Of course, B itself uses A as its own gateway


  3. run tcpdump on B to see what's going on

On a client C, I start any request, e.g.



$ traceroute www.google.com


Now, I expect that traffic originating from C is routed to B, then to A and finally to the internet.



What works. C is able to reach the internet



What does not work. Except for the first request, it seems that B is completely bypassed: tcpdump does not show anything; the address of B doesn't show up in the traceroute output. Still, I'm sure that reroute takes place because C is cut out from internet if I disable IP forwarding on B.



If some sort of short-curcuit is happening, how can I avoid it?



Disclaimer: I know that changing the network topology could solve the "capture all traffic" problem (e.g. by port mirroring etc.), but I really want to understand what's going on with my setup and how to fix that without changing topology.







share|improve this question
















  • 1




    Assuming you wanted to say "C uses B as gateway, while B uses A as gateway", then this will only work if A bridges WLAN and LAN, because otherwise C and B are not in the same segment. So you need to get into the A via ssh or otherwise, and look and possible change what A does. If A just forwards packets from C to the internet, there's nothing you can do unless you can change the way A works (e.g. by flashing it with OpenWRT).
    – dirkt
    Nov 20 '17 at 11:18












up vote
0
down vote

favorite









up vote
0
down vote

favorite











In my home network I have the following topology



 Internet
|
wifi |
C ----------- A ---------- B


where



  • A (static IP 192.168.0.254) is the router/AP given by my ISP.

  • B (static IP 192.168.0.1) is a linux machine working as local DNS and DHCP server (running dnsmasq)

  • C is any client connecting to the AP and configured by DHCP.

For now, the default gateway supplied by B (as DHCP server) is just A.



Then, suppose I want to capture in B all traffic coming from any client C. Here's what I did on B:




  1. activate IP forwarding with



    # sysctl net.ipv4.ip_forward=1"


  2. supply B as gateway. Of course, B itself uses A as its own gateway


  3. run tcpdump on B to see what's going on

On a client C, I start any request, e.g.



$ traceroute www.google.com


Now, I expect that traffic originating from C is routed to B, then to A and finally to the internet.



What works. C is able to reach the internet



What does not work. Except for the first request, it seems that B is completely bypassed: tcpdump does not show anything; the address of B doesn't show up in the traceroute output. Still, I'm sure that reroute takes place because C is cut out from internet if I disable IP forwarding on B.



If some sort of short-curcuit is happening, how can I avoid it?



Disclaimer: I know that changing the network topology could solve the "capture all traffic" problem (e.g. by port mirroring etc.), but I really want to understand what's going on with my setup and how to fix that without changing topology.







share|improve this question












In my home network I have the following topology



 Internet
|
wifi |
C ----------- A ---------- B


where



  • A (static IP 192.168.0.254) is the router/AP given by my ISP.

  • B (static IP 192.168.0.1) is a linux machine working as local DNS and DHCP server (running dnsmasq)

  • C is any client connecting to the AP and configured by DHCP.

For now, the default gateway supplied by B (as DHCP server) is just A.



Then, suppose I want to capture in B all traffic coming from any client C. Here's what I did on B:




  1. activate IP forwarding with



    # sysctl net.ipv4.ip_forward=1"


  2. supply B as gateway. Of course, B itself uses A as its own gateway


  3. run tcpdump on B to see what's going on

On a client C, I start any request, e.g.



$ traceroute www.google.com


Now, I expect that traffic originating from C is routed to B, then to A and finally to the internet.



What works. C is able to reach the internet



What does not work. Except for the first request, it seems that B is completely bypassed: tcpdump does not show anything; the address of B doesn't show up in the traceroute output. Still, I'm sure that reroute takes place because C is cut out from internet if I disable IP forwarding on B.



If some sort of short-curcuit is happening, how can I avoid it?



Disclaimer: I know that changing the network topology could solve the "capture all traffic" problem (e.g. by port mirroring etc.), but I really want to understand what's going on with my setup and how to fix that without changing topology.









share|improve this question











share|improve this question




share|improve this question










asked Nov 20 '17 at 10:59









theuncle

31




31







  • 1




    Assuming you wanted to say "C uses B as gateway, while B uses A as gateway", then this will only work if A bridges WLAN and LAN, because otherwise C and B are not in the same segment. So you need to get into the A via ssh or otherwise, and look and possible change what A does. If A just forwards packets from C to the internet, there's nothing you can do unless you can change the way A works (e.g. by flashing it with OpenWRT).
    – dirkt
    Nov 20 '17 at 11:18












  • 1




    Assuming you wanted to say "C uses B as gateway, while B uses A as gateway", then this will only work if A bridges WLAN and LAN, because otherwise C and B are not in the same segment. So you need to get into the A via ssh or otherwise, and look and possible change what A does. If A just forwards packets from C to the internet, there's nothing you can do unless you can change the way A works (e.g. by flashing it with OpenWRT).
    – dirkt
    Nov 20 '17 at 11:18







1




1




Assuming you wanted to say "C uses B as gateway, while B uses A as gateway", then this will only work if A bridges WLAN and LAN, because otherwise C and B are not in the same segment. So you need to get into the A via ssh or otherwise, and look and possible change what A does. If A just forwards packets from C to the internet, there's nothing you can do unless you can change the way A works (e.g. by flashing it with OpenWRT).
– dirkt
Nov 20 '17 at 11:18




Assuming you wanted to say "C uses B as gateway, while B uses A as gateway", then this will only work if A bridges WLAN and LAN, because otherwise C and B are not in the same segment. So you need to get into the A via ssh or otherwise, and look and possible change what A does. If A just forwards packets from C to the internet, there's nothing you can do unless you can change the way A works (e.g. by flashing it with OpenWRT).
– dirkt
Nov 20 '17 at 11:18










1 Answer
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up vote
0
down vote



accepted










You need host B to do NAT translations so that A does not see the same packet again. Instead B should send out packets through A as if they originated from B. To achieve that you add an iptables rule as follows:



# iptables -t nat -A POSTROUTING -s ip-of-C -j MASQUERADE


By that rule, all packets out from B will be rewritten to be as if sourced from B, but keeping a table of back translations, so that associated responses can be back-translated and sent to C.



Note the -s ... part which limits the rule to only apply to packets sourced from C (or it could be set as the local LAN), and e.g., not the response packets.



EDIT (taking @theuncle's comment into account): The explanation as to why it doesn't work without NAT would be, that host B realizes the packet comes in and goes out unaltered on the same interface, so it can improve networking by telling C to talk directly with A for the traffic concerned.






share|improve this answer






















  • 1) This is not the problem, the problem is that packets from A never reach B. So you can set up NAT on B until you are blue in the face, if there are no packets from A to NAT on B, it won't help. 2) If you control A, you don't need B to do NAT. If you don't control A, you won't be able to fix it.
    – dirkt
    Nov 20 '17 at 12:49






  • 1




    @ralph Thanks, this is helpful and solves my problem. Meantime, I also discovered that my setup, even without the iptables rule you gave, half-works until machine B sends an ICMP Redirect Host message to C.
    – theuncle
    Nov 20 '17 at 18:03











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
0
down vote



accepted










You need host B to do NAT translations so that A does not see the same packet again. Instead B should send out packets through A as if they originated from B. To achieve that you add an iptables rule as follows:



# iptables -t nat -A POSTROUTING -s ip-of-C -j MASQUERADE


By that rule, all packets out from B will be rewritten to be as if sourced from B, but keeping a table of back translations, so that associated responses can be back-translated and sent to C.



Note the -s ... part which limits the rule to only apply to packets sourced from C (or it could be set as the local LAN), and e.g., not the response packets.



EDIT (taking @theuncle's comment into account): The explanation as to why it doesn't work without NAT would be, that host B realizes the packet comes in and goes out unaltered on the same interface, so it can improve networking by telling C to talk directly with A for the traffic concerned.






share|improve this answer






















  • 1) This is not the problem, the problem is that packets from A never reach B. So you can set up NAT on B until you are blue in the face, if there are no packets from A to NAT on B, it won't help. 2) If you control A, you don't need B to do NAT. If you don't control A, you won't be able to fix it.
    – dirkt
    Nov 20 '17 at 12:49






  • 1




    @ralph Thanks, this is helpful and solves my problem. Meantime, I also discovered that my setup, even without the iptables rule you gave, half-works until machine B sends an ICMP Redirect Host message to C.
    – theuncle
    Nov 20 '17 at 18:03















up vote
0
down vote



accepted










You need host B to do NAT translations so that A does not see the same packet again. Instead B should send out packets through A as if they originated from B. To achieve that you add an iptables rule as follows:



# iptables -t nat -A POSTROUTING -s ip-of-C -j MASQUERADE


By that rule, all packets out from B will be rewritten to be as if sourced from B, but keeping a table of back translations, so that associated responses can be back-translated and sent to C.



Note the -s ... part which limits the rule to only apply to packets sourced from C (or it could be set as the local LAN), and e.g., not the response packets.



EDIT (taking @theuncle's comment into account): The explanation as to why it doesn't work without NAT would be, that host B realizes the packet comes in and goes out unaltered on the same interface, so it can improve networking by telling C to talk directly with A for the traffic concerned.






share|improve this answer






















  • 1) This is not the problem, the problem is that packets from A never reach B. So you can set up NAT on B until you are blue in the face, if there are no packets from A to NAT on B, it won't help. 2) If you control A, you don't need B to do NAT. If you don't control A, you won't be able to fix it.
    – dirkt
    Nov 20 '17 at 12:49






  • 1




    @ralph Thanks, this is helpful and solves my problem. Meantime, I also discovered that my setup, even without the iptables rule you gave, half-works until machine B sends an ICMP Redirect Host message to C.
    – theuncle
    Nov 20 '17 at 18:03













up vote
0
down vote



accepted







up vote
0
down vote



accepted






You need host B to do NAT translations so that A does not see the same packet again. Instead B should send out packets through A as if they originated from B. To achieve that you add an iptables rule as follows:



# iptables -t nat -A POSTROUTING -s ip-of-C -j MASQUERADE


By that rule, all packets out from B will be rewritten to be as if sourced from B, but keeping a table of back translations, so that associated responses can be back-translated and sent to C.



Note the -s ... part which limits the rule to only apply to packets sourced from C (or it could be set as the local LAN), and e.g., not the response packets.



EDIT (taking @theuncle's comment into account): The explanation as to why it doesn't work without NAT would be, that host B realizes the packet comes in and goes out unaltered on the same interface, so it can improve networking by telling C to talk directly with A for the traffic concerned.






share|improve this answer














You need host B to do NAT translations so that A does not see the same packet again. Instead B should send out packets through A as if they originated from B. To achieve that you add an iptables rule as follows:



# iptables -t nat -A POSTROUTING -s ip-of-C -j MASQUERADE


By that rule, all packets out from B will be rewritten to be as if sourced from B, but keeping a table of back translations, so that associated responses can be back-translated and sent to C.



Note the -s ... part which limits the rule to only apply to packets sourced from C (or it could be set as the local LAN), and e.g., not the response packets.



EDIT (taking @theuncle's comment into account): The explanation as to why it doesn't work without NAT would be, that host B realizes the packet comes in and goes out unaltered on the same interface, so it can improve networking by telling C to talk directly with A for the traffic concerned.







share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 20 '17 at 21:46

























answered Nov 20 '17 at 11:30









Ralph Rönnquist

2,43738




2,43738











  • 1) This is not the problem, the problem is that packets from A never reach B. So you can set up NAT on B until you are blue in the face, if there are no packets from A to NAT on B, it won't help. 2) If you control A, you don't need B to do NAT. If you don't control A, you won't be able to fix it.
    – dirkt
    Nov 20 '17 at 12:49






  • 1




    @ralph Thanks, this is helpful and solves my problem. Meantime, I also discovered that my setup, even without the iptables rule you gave, half-works until machine B sends an ICMP Redirect Host message to C.
    – theuncle
    Nov 20 '17 at 18:03

















  • 1) This is not the problem, the problem is that packets from A never reach B. So you can set up NAT on B until you are blue in the face, if there are no packets from A to NAT on B, it won't help. 2) If you control A, you don't need B to do NAT. If you don't control A, you won't be able to fix it.
    – dirkt
    Nov 20 '17 at 12:49






  • 1




    @ralph Thanks, this is helpful and solves my problem. Meantime, I also discovered that my setup, even without the iptables rule you gave, half-works until machine B sends an ICMP Redirect Host message to C.
    – theuncle
    Nov 20 '17 at 18:03
















1) This is not the problem, the problem is that packets from A never reach B. So you can set up NAT on B until you are blue in the face, if there are no packets from A to NAT on B, it won't help. 2) If you control A, you don't need B to do NAT. If you don't control A, you won't be able to fix it.
– dirkt
Nov 20 '17 at 12:49




1) This is not the problem, the problem is that packets from A never reach B. So you can set up NAT on B until you are blue in the face, if there are no packets from A to NAT on B, it won't help. 2) If you control A, you don't need B to do NAT. If you don't control A, you won't be able to fix it.
– dirkt
Nov 20 '17 at 12:49




1




1




@ralph Thanks, this is helpful and solves my problem. Meantime, I also discovered that my setup, even without the iptables rule you gave, half-works until machine B sends an ICMP Redirect Host message to C.
– theuncle
Nov 20 '17 at 18:03





@ralph Thanks, this is helpful and solves my problem. Meantime, I also discovered that my setup, even without the iptables rule you gave, half-works until machine B sends an ICMP Redirect Host message to C.
– theuncle
Nov 20 '17 at 18:03


















 

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